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A body released from a great height falls freely towards the earth. Another body is released from the same height exactly one second later. If the separation (in $m$ ) between the two bodies two seconds after the release of the second body is $x \times 12.25$ then find $x$ . ( $g = 9.8 m s^{- 2}$ )

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Important Questions on Motion in a Straight Line

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A stone falls freely under gravity. It covers distance,

d_{1}

and,

d_{2}

in the first

4

seconds, and the next,

8

seconds respectively. The ratio

\frac{d_{2}}{d_{1}}

HARD

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

Two uniformly dense spherical balls of radius

R

and

2 R

are released simultaneously from identical heights. If both the balls hit the ground at the same time, then the ratio of densities of the balls,

ρ_{R} : ρ_{2 R}

is (here,

ρ_{R}

is the density of the ball with radius

R

and

ρ_{2 R}

is the density of the ball with radius

2 R

)

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A ball is projected vertically up with speed

V_{0}

from a certain height

H .

When the ball reaches the ground the speed is

3 V_{0} .

The time taken by the ball to reach the ground and height

H

respectively are.(

g =

the acceleration due to gravity)

MEDIUM

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

An object of mass

5 kg

is thrown vertically upwards from the ground. The air resistance produces a constant retarding force of

10 N

throughout the motion. The ratio of time of ascent to the time of descent will be equal to : [Use

g = 10 {m s}^{- 2}

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A person sitting in the ground floor of a building notices through the window, of height

1.5 m,

a ball dropped from the roof of the building crosses the window in

0.1 s .

What is the velocity of the ball when it is at the topmost point of the window?

(g = 10 m s^{- 2})

MEDIUM

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

Two balls

A

and

B

are placed at the top of

180 m

tall tower. Ball

A

is released from the top at

t = 0 s

. Ball

B

is thrown vertically down with an initial velocity

u

t = 2 s

. After a certain time, both balls meet

100 m

above the ground. Find the value of

u

m s^{- 1}

. [use

g = 10 {m s}^{- 2}

]

HARD

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A balloon was moving upwards with a uniform velocity of

10 m s^{- 1}

. An object of finite mass is dropped from the balloon when it was at a height of

75 m

from the ground level. The height of the balloon from the ground when object strikes the ground was around: (takes the value of

g

10 m s^{- 2}

)

MEDIUM

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

From the top of a tower, a ball is thrown vertically upward which reaches the ground in

6 s

. A second ball thrown vertically downward from the same position with the same speed reaches the ground in

1.5 s

. A third ball released, from the rest from the same location, will reach the ground in _____ s.

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A box filled with water has a small hole on its side near the bottom. It is dropped from the top of a tower. As it falls, a camera attached on the side of the box records the shape of the water stream coming out of the hole. The resulting video will show

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A stone is dropped from the top of a building. When it crosses a point

5 m

below the top, another stone starts to fall from a point

25 m

below the top. Both stones reach the bottom of building simultaneously. The height of the building is :

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A NCC parade is going at a uniform speed of

9 km h^{- 1}

under a mango tree on which a monkey is sitting at a height of

19.6 m

. At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is :
(Given

g = 9.8 m s^{- 2}

)

MEDIUM

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A tennis ball is released from a height

h

and after freely falling on a wooden floor it rebounds and reaches height

h / 2

. The velocity versus height of the ball during its motion may be represented graphically by: (graphs are drawn schematically and on not to scale)

HARD

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws

n

balls per second, the maximum height the balls can reach is

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

Two balls are released from the same position at a height of

500 m

above ground, one after the other, with an interval of

1 s .

What is the distance between the two balls when the first hits ground?
(Acceleration due to gravity

g = 10 m / s^{2}

)

MEDIUM

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A ball is dropped from the top of a

100 m

high tower on a planet. In the last

\frac{1}{2} s

before hitting the ground, it covers a distance of

19 m .

Acceleration due to gravity (in

m s^{- 2}

) near the surface on that planet is______

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A tennis ball is dropped on to the floor from a height of

9.8 m

. It rebounds to a height

5.0 m

. Ball comes in contact with the floor for

0.2 s

. The average acceleration during contact is ______

m s^{- 2}

. [Given

g = 10 m s^{- 2}

]

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A ball of mass

0.5 kg

is dropped from the height of

10 m

. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is _____

m

. [Use

g = 10 m s^{- 2}

]

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

Water-drops are falling at regular intervals from a water tap situated at a height of

5 meters

from the ground. Just at the moment, the first drop touches the ground, the third drop comes out. At that moment, the height of the second drop of water from the ground will be

MEDIUM

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A ball is thrown vertically downward with a velocity of

20 m s^{- 1}

from the top of a tower. It hits the ground after some time with a velocity of

80 m s^{- 1}

. The height of the tower is:

(g = 10 m s^{- 2})

EASY

Physics>Mechanics>Motion in a Straight Line>Kinematic Equations for Uniformly Accelerated Motion

A body is thrown vertically upwards. Which one of the following graphs correctly represents the velocity

(v)

vs time

(t)

A body released from a great height falls freely towards the earth. Another body is released from the same height exactly one second later. If the separation (in m) between the two bodies two seconds after the release of the second body is x×12.25 then find x. (g=9.8 m s-2)

Important Questions on Motion in a Straight Line

Learn and Prepare for any exam you want !

A body released from a great height falls freely towards the earth. Another body is released from the same height exactly one second later. If the separation (in $m$ ) between the two bodies two seconds after the release of the second body is $x \times 12.25$ then find $x$ . ( $g = 9.8 m s^{- 2}$ )