A capacitor of capacitance $C_0$ is charged to a voltage $V_0$ and then isolated. An uncharged capacitor $C$ is then charged from $C_0$, discharged and charged again; the process is repeated $n$ times. Due to this, the potential of the $C_0$ is decreased to $V$, then the value of $C$ is:

A network of uncharged capacitors and resistances is as shown.

Current through the battery immediately after the key, $K$ is closed and after a long time interval is:

Six capacitors each of capacitance $C$ is connected as shown in the figure and initially all the capacitors are uncharged. Now a battery of $\mathrm{emf} =\mathrm{\epsilon }$ is connected. How much charge will flow through the battery if the switch is on?

The equivalent capacitance between point $A$ and $B$ is

$C_1=3 \mathrm{\mu F}, C_2=6 \mathrm{\mu F} \mathrm{and} C_3=2 \mathrm{\mu F}$, then equivalent capacitance between $a$ and $b$ is

$C_1=3 \mathrm{\mu F}, C_2=6 \mathrm{\mu F} \mathrm{and} C_3=2 \mathrm{\mu F}$. If a potential difference of $48 \mathrm{V}$ is applied across points $a$ and $b$, then charge on the capacitor ${\mathrm{C}}_3$ at steady state condition will be 

The $V$ versus $x$-plot for six identical metal plates of cross-sectional area $A$ is as shown. The equivalent capacitance between $2$ and $5$ is (adjacent plates are placed at a separation $d$)