A hall is 10 m long, 5 m wide and 4 m high. It has one door 2 m by 1 m and 2 Windows 1 m by 80 c m . Find the area of the 4 walls (excluding the door and windows)

We have, A hall is 10 m long, 5 m wide and 4 m high. It has one door 2 m by 1 m and 2 Windows 1 m by 80 c m . Now we know that, The area of four walls is 2 l + b × h , where l is the length, b is the width and h is the height of the room Then area of four walls is 2 10 + 5 × 4 = 120 m 2 Now area of one door is 2 × 1 = 2 m 2 And the area of two windows is 2 1 × 80 100 = 1 . 6 m 2 Combined area of one door and two windows is 2 + 1 . 6 = 3 . 6 m 2 Therefore, the area of the 4 walls (excluding the door and windows) = Total area of four walls - Combined area of one door and two windows = 120 - 3 . 6 = 116 . 4 m 2

A hall is 10 m long, 5 m wide and 4 m high. It has one door 2 m by 1 m and 2 Windows 1 m by 80 c m . The area of the 4 walls (excluding the door and windows). Find the cost of distempering the walls at ₹ 50 per m 2 .

We have, A hall is 10 m long, 5 m wide and 4 m high. It has one door 2 m by 1 m and 2 Windows 1 m by 80 c m . Now we know that, The area of four walls is 2 l + b × h , where l is the length, b is the width and h is the height of the room Then area of four walls is 2 10 + 5 × 4 = 120 m 2 Now area of one door is 2 × 1 = 2 m 2 And the area of two windows is 2 1 × 80 100 = 1 . 6 m 2 Combined area of one door and two windows is 2 + 1 . 6 = 3 . 6 m 2 Then, the area of the 4 walls (excluding the door and windows) = Total area of four walls - Combined area of one door and two windows = 120 - 3 . 6 = 116 . 4 m 2 Therefore, the cost of distempering the walls is ₹ 50 × 116 . 4 = ₹ 5820

A hall is 10 m long, 5 m wide and 4 m high. It has one door 2 m by 1 m and 2 Windows 1 m by 80 c m . Find the cost of polishing the floor at the rate of ₹ 5 per m 2 .

We have, A hall is 10 m long, 5 m wide and 4 m high. It has one door 2 m by 1 m and 2 Windows 1 m by 80 c m . Now we know that, Area of rectangle is length × breadth Then, The area of floor is 10 5 = 50 m 2 Therefore, the cost of polishing the floor is ₹ 5 × 50 = ₹ 250

MEDIUM

9th ICSE

IMPORTANT

Earn 100

A certain quality of wood costs $₹ 67, 500$ per $m^{3}$ . A solid cubical block of such wood is bought for $₹ 4320$ . Calculate the volume of the block and find the length of one edge of the block.

Important Questions on Surface Area and Volume of Solids

HARD

9th ICSE

IMPORTANT

ICSE MATHEMATICS CLASS 9>Chapter 18 - Surface Area and Volume of Solids>EXERCISE 18>Q 24

A hall is

10 m

long,

5 m

wide and

4 m

high. It has one door

2 m

1 m

and

2

Windows

1 m

80 c m

. Find the area of the

4

walls (excluding the door and windows)

HARD

9th ICSE

IMPORTANT

ICSE MATHEMATICS CLASS 9>Chapter 18 - Surface Area and Volume of Solids>EXERCISE 18>Q 24

A hall is

10 m

long,

5 m

wide and

4 m

high. It has one door

2 m

1 m

and

2

Windows

1 m

80 c m

. The area of the

4

walls (excluding the door and windows).

Find the cost of distempering the walls at $₹ 50$ per $m^{2}$ .

EASY

9th ICSE

IMPORTANT

ICSE MATHEMATICS CLASS 9>Chapter 18 - Surface Area and Volume of Solids>EXERCISE 18>Q 24

A hall is

10 m

long,

5 m

wide and

4 m

high. It has one door

2 m

1 m

and

2

Windows

1 m

80 c m

. Find the cost of polishing the floor at the rate of

₹ 5

per

m^{2}

HARD

9th ICSE

IMPORTANT

ICSE MATHEMATICS CLASS 9>Chapter 18 - Surface Area and Volume of Solids>EXERCISE 18>Q 25

$A B C D$ is the cross-section of a metal container in a paint factory. If $A B = 2.4 m, D C = 1.6 m, B Q = C R = 1.2 m$ and height of the container is $1.1 m$ , find the volume of paint in the container.

Question Image

HARD

9th ICSE

IMPORTANT

ICSE MATHEMATICS CLASS 9>Chapter 18 - Surface Area and Volume of Solids>EXERCISE 18>Q 25

$A B C D$ is the cross-section of a metal container in a paint factory. If $A B = 2.4 m, D C = 1.6 m, B Q = C R = 1.2 m$ and height of the container is $1.1 m$ , find the cost of paint at $₹ 40$ per litre. [ $1 m^{3} = 1000$ litres]

Question Image

HARD

9th ICSE

IMPORTANT

ICSE MATHEMATICS CLASS 9>Chapter 18 - Surface Area and Volume of Solids>EXERCISE 18>Q 26

Calculate the quantity of water in a swimming pool which is

50 m

long,

12 m

wide and the shallow and deep ends are

1.5 m

and

3 m

respectively

HARD

9th ICSE

IMPORTANT

ICSE MATHEMATICS CLASS 9>Chapter 18 - Surface Area and Volume of Solids>MISCELLANEOUS EXERCISE>Q 1

A closed storage container consists of a cuboid $A B D E P O S T$ to which a quadrant of a cylinder $B C D Q R S$ is attached as shown in the figure. $A E = 20 c m, E D = 30 m, D C = 20 c m$ and $C R = 70 c m$ . Taking $π = 3.14$

Calculate the area of the face $A B C D E$

Question Image

HARD

9th ICSE

IMPORTANT

ICSE MATHEMATICS CLASS 9>Chapter 18 - Surface Area and Volume of Solids>MISCELLANEOUS EXERCISE>Q 1

Calculate the volume of the container.

Question Image

A certain quality of wood costs ₹ 67,500 per m3. A solid cubical block of such wood is bought for ₹ 4320. Calculate the volume of the block and find the length of one edge of the block.

Important Questions on Surface Area and Volume of Solids

Learn and Prepare for any exam you want !

A certain quality of wood costs $₹ 67, 500$ per $m^{3}$ . A solid cubical block of such wood is bought for $₹ 4320$ . Calculate the volume of the block and find the length of one edge of the block.