A charge $Q_1$ is placed at $\mathrm{O}$ inside a hollow conducting sphere having inner and outer radii as $10 \mathrm{m}$ and $11 \mathrm{m}$ as shown. The force experienced by $Q_2$ at $\mathrm{P}$ is $F_1$, and force experienced by $Q_2$ when $Q_1$ is placed at $O_1$ is $F_2$. Then $\frac{F_1}{F_2}$ is equal to

Consider Gauss's law:

$\oint \overrightarrow{E}·\overrightarrow{d}s=\frac{q}{{\epsilon }_0}$

Then, for the situation shown in figure at the Gaussian surface

Consider a Gaussian spherical surface covering a dipole of charge $q$ and $-q,$ then

Two large thin conducting plates with a small gap in between are placed in a uniform electric field $E$ (perpendicular to the plates). The area of each plate is $A,$ and charges $+Q$ and $-Q$ are given to these plates as shown in figure. If $R, S,$ and $T$ are three points in space, then the

The figure shows a point charge of $0.5\times {10}^{-6} \mathrm{C}$ at the centre of a spherical cavity of radius $3 \mathrm{cm}$ of a piece of metal. The electric field at,

A right circular imaginary cone is shown in the figure. $A, B,$ and $C$ are the points in the plane containing the base of the cone, while $D$ is the point at the vertex of the cone. If ${\mathrm{\varphi }}_{\mathrm{A}}\text{,} {\mathrm{\varphi }}_{\mathrm{B}}\text{,} {\mathrm{\varphi }}_{\mathrm{C}}$ and ${\mathrm{\varphi }}_{\mathrm{D}}$ represent the flux through the curved surface of the cone when a point charge $Q$ is at points $A\text{,} B\text{,} C\text{,}$ and $D$ respectively, then