A closed cylinder of radius $R$ and length $L$ is placed in a uniform electric field $E,$ parallel to the axis of the cylinder. Then the electric flux through the cylinder must be -

As shown in the figure, a charge  is placed at the centre of the cubical vessel (with one face open) is placed at the centre of the cubical vessel (with one face open) as shown in the figure. The flux of the electric field through the surface of the vessel is

Electric charge is uniformly distributed along a long straight wire of radius $1 \mathrm{mm}.$ The charge per $\mathrm{cm}$ length of the wire is $Q$ coulomb. Another cylindrical surface of radius $50 \mathrm{cm}$ and length $1 \mathrm{m}$ symmetrically encloses the wire as shown in fig. The total electric flux passing through the cylindrical surface is -

If a square coil is making an angle $60°$ with electric field $E$ according to figure, the electric flux passing through the square coil is (the side of square is $4 \mathrm{cm}$):

A square surface of side $L \mathrm{m}$ is in the plane of the paper. A uniform electric field $\overrightarrow{E }\left(\mathrm{V} {\mathrm{m}}^{-1}\right),$ also in the plane of the paper, is limited only to the lower half of the square surface, (see figure). The electric flux in SI units associated with the surface is: