A compound which contains one atom of $\mathrm{X}$ and two atoms of $\mathrm{Y}$ for each three atoms of $\mathrm{Z}$, is made by mixing $5.00 \mathrm{g}$ of $\mathrm{X}$, $1.15\times {10}^{23}$ atoms of $\mathrm{Y}$ and $0.03 \mathrm{mole}$ of $\mathrm{Z}$ atoms. Given that only $40 \mathrm{g}$ of compound results, calculate the atomic weight of $\mathrm{Y}$, if the atomic weight of $\mathrm{X}$ and $\mathrm{Z}$ are $60$ and $80 \mathrm{amu}$, respectively. 

For the reaction given below, calculate the mass of $\mathrm{FeO}$ produced from $2 \mathrm{g} \mathrm{VO}$ and $5.75 \mathrm{g}$ of ${\mathrm{Fe}}_2{\mathrm{O}}_3$. Also, report the limiting reagent.

$\mathrm{VO}+{\mathrm{Fe}}_2{\mathrm{O}}_3⟶\mathrm{FeO}+{\mathrm{V}}_2{\mathrm{O}}_5$

Carbon disulphide ${\mathrm{CS}}_2$ can be made from the by-product of ${\mathrm{SO}}_2$. The overall reaction is: 

$5\mathrm{C}+2{\mathrm{SO}}_2⟶{\mathrm{CS}}_2+4\mathrm{CO}$

How much of ${\mathrm{CS}}_2$ can be produced from $440 \mathrm{kg}$ of waste ${\mathrm{SO}}_2$ with $60 \mathrm{kg}$ of coke, if the ${\mathrm{SO}}_2$ conversion is $80\%$?
 

Calculate the amount of $\mathrm{Ni}$ needed in the Mond's process given below.

$\mathrm{Ni}+4\mathrm{CO}⟶\mathrm{Ni}(\mathrm{CO}{)}_4$

If $\mathrm{CO}$ used in this process is obtained through a process, in which $6 \mathrm{g}$ of carbon is mixed with $44 \mathrm{g} {\mathrm{CO}}_2$.

$\mathrm{NX}$ is produced by the following steps of reaction: 

$\mathrm{M}+{\mathrm{X}}_2⟶{\mathrm{MX}}_2$

$3{\mathrm{MX}}_2+{\mathrm{X}}_2⟶{\mathrm{M}}_3{\mathrm{X}}_8$

${\mathrm{M}}_3{\mathrm{X}}_8+{\mathrm{N}}_2{\mathrm{CO}}_3⟶\mathrm{NX}+{\mathrm{CO}}_2+{\mathrm{M}}_3{\mathrm{O}}_4$

How much $\mathrm{M}$ (metal) is consumed to produce $206 \mathrm{g}$ of $\mathrm{NX}$? $\left(\mathrm{Take} \mathrm{Atomic} \mathrm{weight} \mathrm{M}=56, \mathrm{N}=23, \mathrm{X}=80\right)$