A constant force $F$ is applied in horizontal direction as shown. Contact force between $M$ and $m$ is $N$ and between $m$ and $M^{\text{'}}$ is $N^{\text{'}}$ then

 

A mass $M$ is suspended by a rope from a rigid support at $A$ as shown in figure. Another rope is tied at the end $B$, and it is pulled horizontally with a force $F$. If the rope $AB$ makes an angle $\mathrm{\theta }$ with the vertical in equilibrium, then the tension in the string $AB$ is

In the system shown in the figure, the acceleration of the $1 \mathrm{kg}$ mass and the tension in the string connecting between $A$ and $B$ is:

A body of mass $8 \mathrm{kg}$ is hanging from another body of mass $12 \mathrm{kg}$. The combination is being pulled by a string with an acceleration of $2.2 \mathrm{m} {\mathrm{s}}^{–2}$. The tension $T_1$ and $T_2$ will be respectively: (use $g=9.8 \mathrm{m} {\mathrm{s}}^{-2}$)

A heavy block kept on a frictionless surface and being pulled by two ropes of equal mass $m$ as shown in figure. At $t=0$, the force on the left rope is withdrawn but the force on the right end continues to act. Let $F_1$ and $F_2$ be the magnitudes of the forces by the right rope and the left rope on the block, respectively.

A block is dragged on smooth plane with the help of a rope which moves with velocity $v$. The horizontal velocity of the block is

Two masses are connected by a string which passes over a pulley accelerating upward at a rate $A$ as shown. If $a_1$ and $a_2$ be the acceleration of bodies $1$ and $2$, respectively, then: