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A crystal is made of particles $X, Y$ and $Z$ . $X$ forms fcc packing. $Y$ occupies all the octahedral voids of $X$ and $Z$ occupies all the tetrahedral voids. If all the particles along one body diagonal are removed then the formula of the crystal would be :-

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Important Questions on Solid State

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Chemistry>Physical Chemistry>Solid State>Voids

Ga

(atomic mass

70 u

) crystallizes in a hexagonal close packed structure. The total number of voids in

0.581 g

Ga

is ________

\times 10^{21}

. (Round off to the Nearest Integer).

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Chemistry>Physical Chemistry>Solid State>Voids

A crystal is made up of metal ions

' M_{1}'

and

' M_{2}'

and oxide ions. Oxide ions form a ccp lattice structure. The cation

' M_{1}'

occupies

50 %

of octahedral voids and the cation

' M_{2}'

occupies

12.5 %

of tetrahedral voids of oxide lattice. The oxidation numbers of

' M_{1}'

and

' M_{2}'

are respectively :

EASY

Chemistry>Physical Chemistry>Solid State>Voids

The number of octahedral voids per lattice site in a lattice is_. (Rounded off to the nearest integer)

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Chemistry>Physical Chemistry>Solid State>Voids

What is the number of octahedral void(s) per atom present in a cubic close-packed structure ?

HARD

Chemistry>Physical Chemistry>Solid State>Voids

If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesium ions, m and n, respectively, are

EASY

Chemistry>Physical Chemistry>Solid State>Voids

A crystalline solid is made up of

X

and

Y

atoms,

X

atoms possesses CCP structure and

Y

atoms are arranged in tetrahedral voids. If all the atoms situated on a diagonal of one side are removed, what will be the molecular formula of the crystalline solid?

HARD

Chemistry>Physical Chemistry>Solid State>Voids

In a cubic closed packed structure of mixed oxide, the oxide ions are in CCP arrangement.

\frac{1}{6}

of tetrahedral voids are occupied by cations

A

and

\frac{1}{2}

of octahedral voids are occupied by cations

B

. The formula of the oxide is

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Chemistry>Physical Chemistry>Solid State>Voids

The edge length of a solid possessing cubic unit cell is $2 \sqrt{2} r$ (structure I), based on hard sphere model, which upon subjecting to a phase transition, a new cubic structure (structure II) having an edge length of $\frac{4 r}{\sqrt{3}}$ is obtained, where $r$ is the radius of the hard sphere. Which of the following statements is true ?

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Chemistry>Physical Chemistry>Solid State>Voids

An element has a face-centered cubic

(fcc)

structure with a cell edge of

a

. The distance between the centres of two nearest tetrahedral voids in the lattice is

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Chemistry>Physical Chemistry>Solid State>Voids

A compound is formed by cation

C

and anion

A

. The anions form hexagonal close packed (hcp) lattice and the cations occupy

75 %

of octahedral voids. The formula of the compound is:

EASY

Chemistry>Physical Chemistry>Solid State>Voids

Right option for the number of tetrahedral and octahedral voids in hexagonal primitive unit cell are:

EASY

Chemistry>Physical Chemistry>Solid State>Voids

An ionic compound is formed between a metal M and non-metal

Y.

M

occupies half the octahedral voids in the cubic close - packed arrangement formed by

Y,

the chemical formula of the ionic compound is

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Chemistry>Physical Chemistry>Solid State>Voids

The empirical formula for a compound with a cubic close packed arrangement of anions and with cations occupying all the octahedral sites in

A_{x} B .

The value of

x

is (Integer answer)

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Chemistry>Physical Chemistry>Solid State>Voids

In a binary compound, atoms of element

A

form a hcp structure and those of element

M

occupy

2 / 3

of the tetrahedral voids of the hcp structure. The formula of the binary compound is:

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Chemistry>Physical Chemistry>Solid State>Voids

In CCP arrangement, the total number of octahedral voids are _________

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Chemistry>Physical Chemistry>Solid State>Voids

The ionic radii of

A^{+}

and

B^{-}

ions are

0.98 \times 10^{- 10} m

and

1.81 \times 10^{- 10} m

. The coordination number of each ion in AB is

MEDIUM

Chemistry>Physical Chemistry>Solid State>Voids

Atoms of element

X

form

hcp

lattice and those of element

Y

occupy

\frac{2}{3}

of its tetrahedral voids. The percentage of element

X

in the lattice is (Nearest integer)

HARD

Chemistry>Physical Chemistry>Solid State>Voids

An element crystallises in a face–centred cubic (fcc) unit cell with cell edge a. The distance between the centres of two nearest octahedral voids in the crystal lattice is:

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Chemistry>Physical Chemistry>Solid State>Voids

The total number of octahedral void (s) per atom present in a cubic close packed structure is :

EASY

Chemistry>Physical Chemistry>Solid State>Voids

A compound of formula

A_{2} B_{3}

has the HCP lattice. Which atom forms the HCP lattice and what fraction of the tetrahedral voids are occupied by the other atoms?

A crystal is made of particles X,Y and Z. X forms fcc packing. Y occupies all the octahedral voids of X and Z occupies all the tetrahedral voids. If all the particles along one body diagonal are removed then the formula of the crystal would be :-

Important Questions on Solid State

Learn and Prepare for any exam you want !

A crystal is made of particles $X, Y$ and $Z$ . $X$ forms fcc packing. $Y$ occupies all the octahedral voids of $X$ and $Z$ occupies all the tetrahedral voids. If all the particles along one body diagonal are removed then the formula of the crystal would be :-