A bag contains 3 red balls and 5 black balls.A ball is drawn at random from the bag.What is the probability that the ball drawn is Red,Black ,Not Red.

Given, Number of Red ball = 3 Number of Black ball = 5 Total number of balls in the bag = 3 + 5 = 8 Probability of drawing a red ball = Number of red ball Total number of balls = 3 8 Probability of drawing a black ball = Number of black ball Total number of balls = 5 8 Probability of not drawing a red ball = 1 - Probability of drawing a red ball = 1 - 3 8 = 5 8

What will be the addition of the probability of incident " E " and incident " E not".

Let the probability of incident " E " is p E And probability of incident " E not" is p E ' Thus, We know that, Probability of an event that is certain to happen is 1 So, p E = 1 And Probability of an event that can not happen is 0 So, p E ' = 0 p E + p E ' = 1 + 0 = 1 Hence, The addition of the probability of incident " E " and incident " E not" is 1

A box contains 5 red marbles, 8 white marbles and 4 green marbles. 1 marble is taken out from the box at random.What is the probability that marble taken out is red,white and not green

Given that, Red marbles = 5 White marbles = 8 Green marbles = 4 Total number of marbles = 5 + 8 + 4 = 17 Probability of getting Red marble Number of red marbles = 5 Probability of drawing a red marble = N u m b e r o f r e d m a r b l e s T o t a l n u m b e r o f m a r b l e s = 5 17 Similarly, Probability of drawing a white marble Number of white marbles = 8 Probability of drawing a white marble = N u m b e r o f w h i t e m a r b l e s T o t a l n u m b e r of m a r b l e s = 8 17 Now Number of green marbles = 4 Probability of drawing a green marble = N u m b e r o f g r e e n m a r b l e s T o t a l n u m b er o f m a r b l e s = 4 17 Hence, probability of not drawing a green marble = 1 - 4 17 = 13 17

What will be the addition of the probability of incident " E " and incident " E not".

Let the probability of incident " E " is p E And probability of incident " E not" is p E ' Thus, We know that, Probability of an event that is certain to happen is 1 So, p E = 1 And Probability of an event that can not happen is 0 So, p E ' = 0 p E + p E ' = 1 + 0 = 1 Hence, The addition of the probability of incident " E " and incident " E not" is 1