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A dihybrid plant on self pollination, produced 400 phenotypes with 9 types of genotype. How many seeds will have genotype TtRr:-

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Important Questions on Principles of Inheritance and Variation

MEDIUM
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If two pea plants having red (dominant) coloured flowers with unknown genotypes are crossed, 75% of the flowers are red and 25% are white. The
genotypic constitution of the parents having red coloured flowers will be :-
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In a dihybrid cross where two parents differ in two pairs of contrasting traits like seed colour yellow (YY) and seed colour green (yy) with seed shape round
(RR) and seed shape wrinkled (rr). The number of green coloured seeds (yy) among sixteen products of F2 generation will be :-
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"When two pairs of traits are combined in a hybrid, segregation of one pair of characters is independent of the other pair of characters". This explains-
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Which of the following is not observed in a monohybrid cross-
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Female Question Image AB Ab aB ab
gametes ? AaBB AaBb aaBB aaBb

In the Punnet square given above, the genotype of the female parent and male parents respectively:

HARD
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When AABBcc is crossed with AaBbCc then the ratio of hybrid for all the three genes is :
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In a plant, red fruit (R) is dominant over yellow fruit (r) and tallness (T) is dominant over shortness (t). If a plant with RRTt genotype is crossed with a plant that is rrtt :-