The rate constant for the first order reaction is given by log 10 k = 14 . 34 - 1 . 25 × 10 4 T . Calculate activation energy of the reaction.

As we know that lnK = ln A - E a RT - - - - - - - ( 1 ) log 10 k = 14 . 34 - 1 . 25 × 10 4 T - - - - - - - ( 2 ) Given Comparing (1) and (2) we will come to know that E a 2 . 303 R = 1 . 25 × 10 4 So, E a = 2 . 303 × 1 . 25 × 10 4 × R E a = 2 . 303 × 1 . 25 × 10 4 × 8 . 314 E a = 239 . 34 kJ