Find the area swept in one minute by a minute hand of a clock of length 12 cm . (Do not substitute for π ).

To find: The area swept in one minute by a minute hand of a clock of length 12 cm . As we know that the minute hand of a clock completes a complete angle i.e., 360 ° of angle in one hour i.e., 60 minutes. So, the minute hand completes 360 ° 60 ° = 6 ° angle after each minute. Now the given minute hand of the clock is behaving as the radius and the area swept is the area of the sector with angle 6 ° and radius 12 cm . The area of the sector with radius r and angle θ = θ 360 ° × π r 2 = 6 ° 360 ° × π × 12 2 cm 2 = 12 5 cm 2 Hence, Required area = 2 . 4 cm 2

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 12 - Areas Related to Circles>Goa Board-2018>Q 3

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A flower bed in the form of a rectangle of dimensions $25 m \times 14 m$ with semicircles on the outer side of the shorter sides of the rectangle as shown in the fig. Calculate the number of rose plants that can be planted if each plant requires $2 m \times 2 m$ area.

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Important Questions on Areas Related to Circles

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 12 - Areas Related to Circles>Goa Board-2019>Q 4

The area of a ring whose outer and inner radii are

5 c m

and

2 c m

respectively is

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 12 - Areas Related to Circles>Goa Board-2019>Q 5

In a circle of a radius

12 c m

, an arc subtends an angle of

60 °

at the centre. Therefore, the length of the arc is

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 12 - Areas Related to Circles>Goa Board-2019>Q 6

In the adjoining figure, $A B C$ is a right triangle with $∠ B = 90 °,$ $AB = 8 cm$ and $CB = 6 cm$ . With $A C$ as a diameter a semicircle is drawn and with $B C$ as radius a quadrant of a circle is drawn, as shown in the figure. Find the area of the shaded region.