MEDIUM

Agniveer Vayu

IMPORTANT

Earn 100

A force acts on a body and displaces it in its direction. The graph shows the relation between the force and displacement, the work done by the force is

60.87% studentsanswered this correctly

Important Questions on Work, Energy and Power

EASY

Agniveer Vayu

IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 6 - Work, Energy and Power>Exercise>Q 2

A force F is applied to the initially stationary cart. The variation of force with time is shown in the figure. The speed of cart at t = 5 sec is -

Question Image

EASY

Agniveer Vayu

IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 6 - Work, Energy and Power>Exercise>Q 3

The relationship between the force

F

and position

x

of a body is as shown in figure. The work done in displacing the body from

x = 1 m to x = 5 m

will be-

EASY

Agniveer Vayu

IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 6 - Work, Energy and Power>Exercise>Q 4

Under the action of a force, a 2 kg body moves such that its position

x

as a function of time

t

is given by t³/3, where

x

is in metre and

t

in second. The work done by the force in the first two seconds is

EASY

Agniveer Vayu

IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 6 - Work, Energy and Power>Exercise>Q 5

A position-dependent force

F = 3 x^{2} - 2 x + 7

acts on a body of mass

7 kg

and displaces it from

x = 0 m

x = 5 m

. The work done on the body is

x^{'}

joule. If both

F

and

x

are measured in SI units, the value of

x^{'}

EASY

Agniveer Vayu

IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 6 - Work, Energy and Power>Exercise>Q 6

A force

\vec{F} = (3 t \hat{i} + 5 \hat{j}) N

acts on a body due to which its position varies as

\vec{s} = (2 t^{2} \hat{i} - 5 \hat{j})

. The work done by this force in the initial

2 s

EASY

Agniveer Vayu

IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 6 - Work, Energy and Power>Exercise>Q 7

When a rubber-band is stretched by a distance $x$ , it exerts a restoring force of magnitude $F = a x + b x^{2}$ where a and b are constants. The work done in stretching the un stretched rubber-band by $L$ is

EASY

Agniveer Vayu

IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 6 - Work, Energy and Power>Exercise>Q 8

Displacement of an object of mass

2 k g

varies as

s = 3 t^{2} + 5 .

Find work done by man from

t = 0

t = 5 s e c .

MEDIUM

Agniveer Vayu

IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 6 - Work, Energy and Power>Exercise>Q 1

100 g

light bulb dropped from a tower reaches a velocity of

20 m s^{- 1}

after falling through

100 m

. The energy transferred to the air due to viscous force is

A force acts on a body and displaces it in its direction. The graph shows the relation between the force and displacement, the work done by the force is

Important Questions on Work, Energy and Power

Learn and Prepare for any exam you want !