A fruit basket had 10 dozen mangoes. Out of these 1 15 got spoilt and 1 3 were eaten. How many mangoes are left?

Given:A fruit basket had 10 dozen mangoes. Out of these 1 15 got spoilt and 1 3 were eaten. Number of mangoes in a fruit basket = 10 dozen = 10 × 12 = 120 So, the number of mangoes got spoilt = 1 15 of 120 . = 1 15 × 120 = 8 And also, the number of mangoes were eaten = 1 3 of 120 = 1 3 × 120 = 40 Thus, the number of mangoes left = 120 - 8 + 40 = 120 - 48 = 72 Therefore, 72 mangoes left are left.

A fruit basket had 10 dozen mangoes. Out of these 1 15 got spoilt and 1 3 were eaten. How many mangoes are left?

Given:A fruit basket had 10 dozen mangoes. Out of these 1 15 got spoilt and 1 3 were eaten. Number of mangoes in a fruit basket = 10 dozen = 10 × 12 = 120 So, the number of mangoes got spoilt = 1 15 of 120 . = 1 15 × 120 = 8 And also, the number of mangoes were eaten = 1 3 of 120 = 1 3 × 120 = 40 Thus, the number of mangoes left = 120 - 8 + 40 = 120 - 48 = 72 Therefore, 72 mangoes left are left.

A lady went to market with ₹ 2000 in her purse and spent 1 4 on fruits and vegetables and 2 5 on provisions. How much money was left with her after the purchase?

Given: A lady went to market with ₹ 2000 in her purse and spent 1 4 on fruits and vegetables and 2 5 on provisions. So, the money spent on fruits and vegetables = 1 4 of ₹ 2000 . = 1 4 × ₹ 2000 = ₹ 500 And also, the money spent on provisions = 2 5 of ₹ 2000 = 2 5 × ₹ 2000 = ₹ 800 Thus, the money left with her after the purchase = ₹ 2000 - ₹ 500 + ₹ 800 = ₹ 2000 - ₹ 1300 = ₹ 700 Therefore, the money left with her is ₹ 700 .

Simplify the following. 3 1 5 ÷ 2 3 5 of 1 1 2

We have to simplify 3 1 5 ÷ 2 3 5 of 1 1 2 Now, 3 1 5 ÷ 2 3 5 of 1 1 2 can be written as 3 1 5 ÷ 2 3 5 × 1 1 2 = 16 5 ÷ 13 5 × 3 2 [By converting mixed fractions to improper fractions] = 16 5 × 5 13 × 3 2 = 8 13 × 3 = 24 13 = 1 11 13 Hence, 3 1 5 ÷ 2 3 5 of 1 1 2 = 1 11 13

Simplify the following. 1 3 - 3 5 + 1 12 of 1 1 2 ÷ 3 4

The given expression is 1 3 - 3 5 + 1 12 of 1 1 2 ÷ 3 4 According to the BODMAS rule, if an expression contains brackets ((), {}, []) we have first to solve or simplify the bracket followed by 'order' (that means powers and roots, etc.), then division, multiplication, addition and subtraction from left to right. Now, 1 3 - 3 5 + 1 12 of 1 1 2 ÷ 3 4 = 1 3 - 3 5 + 1 12 × 3 2 ÷ 3 4 = 1 3 - 3 5 + 1 8 ÷ 3 4 = 1 3 - 3 5 + 1 8 × 4 3 = 1 3 - 3 5 + 1 2 × 1 3 = 1 3 - 3 5 + 1 6 = 10 30 - 18 30 + 5 30 = 10 - 18 + 5 30 = - 3 30 = - 1 10 Hence, 1 3 - 3 5 + 1 12 of 1 1 2 ÷ 3 4 = - 1 10 .

Simplify the following. 11 169 ÷ 121 225 ÷ 15 13

The given expression is 11 169 ÷ 121 225 ÷ 15 13 According to the BODMAS rule, if an expression contains brackets ((), {}, []) we have first to solve or simplify the bracket followed by 'order' (that means powers and roots, etc.), then division, multiplication, addition and subtraction from left to right. Now, 11 169 ÷ 121 225 ÷ 15 13 = 11 169 × 225 121 ÷ 15 13 = 1 169 × 225 11 ÷ 15 13 = 225 169 × 11 ÷ 15 13 = 225 169 × 11 × 13 15 = 15 13 × 11 = 15 143 Hence, 11 169 ÷ 121 225 ÷ 15 13 = 15 143 .

Simplify the following. 3 1 2 - 2 3 4 of 4 9 + 5 14 ÷ 2 1 7

The given expression is 3 1 2 - 2 3 4 of 4 9 + 5 14 ÷ 2 1 7 When brackets are present, we follow BODMAS rule. Apart from the operations of division, multiplication, addition and subtraction, we drop brackets one by one in the order of , and . Now, 3 1 2 - 2 3 4 of 4 9 + 5 14 ÷ 2 1 7 = 7 2 - 11 4 of 4 9 + 5 14 ÷ 15 7 = 14 4 - 11 4 of 4 9 + 5 14 ÷ 15 7 = 14 - 11 4 of 4 9 + 5 14 ÷ 15 7 = 3 4 of 4 9 + 5 14 ÷ 15 7 = 3 4 × 4 9 + 5 14 ÷ 15 7 = 1 3 + 5 14 ÷ 15 7 = 1 3 + 5 14 × 7 15 = 1 3 + 1 2 × 1 3 = 1 3 + 1 6 = 2 6 + 1 6 = 2 + 1 6 = 3 6 = 1 2 Hence, 3 1 2 - 2 3 4 of 4 9 + 5 14 ÷ 2 1 7 = 1 2 .