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A helium nucleus is moving in a circular path of radius 0.8m. If it takes 2 sec to complete one revolution. Magnetic field produced at the centre of the circle :- 

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Important Questions on Magnetic Effect of Current

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A cell of an emf of, 2 V and internal resistance of 0.5 Ω is sending current through a tangent galvanometer of resistance, 4.5 Ω . If another external resistance of 95 Ω is introduced, the deflection of the galvanometer is, 45º. The reduction factor of the galvanometer is:- 
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Following is a square shape loop, whose one arm BC produces a magnetic field B at the center of the coil. The resultant magnetic field due to all the arms will be:- 

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A wire is parallel to one arm of a square current-carrying loop, which also carries current. Now at any point A within the coil, the magnetic field will be:-

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A current of 10 A is established in a long wire along the positive z-axis. Find the magnetic field B at the point 1 m, 0, 0
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 The radius of the current-carrying coil is, R. Then the ratio of magnetic fields at the centre of the coil to the axial point, which is R3, distance away from the centre of the coil:- 
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 A coil of one loop is made by a wire of length L and there after a coil of two loops is made by same wire. The ratio of magnetic field at the centre of coils respectively :- 
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Assume the given diagram a combination of complete circle and two semi-infinite wires. Magnetic field at point O will be:

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