A horizontal force of $10\mathrm{N}$ is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and the wall is $0.2$. The weight of the block is:

 

Two blocks of masses $M=5 \mathrm{kg}$ and $m=3 \mathrm{kg}$ are placed on a horizontal surface as shown in fig. The coefficient of friction between the blocks is $0.5$ and that between the block $M$ and the horizontal surface is $0.7$. What is the maximum horizontal force $F$ that can be applied to block $M$ so that the two blocks move without slipping ? Take $g=10 \mathrm{m}/{\mathrm{s}}^2$

A mass $\mathrm{M}=50 \mathrm{kg}$ is suspended with the use of strings $\mathrm{A},\mathrm{B}$ and $\mathrm{C}$ as shown in fig. W is a vertical wall and $\mathrm{R}$ is a rigid horizontal rod. The tension in the string $\mathrm{B}$ is:

A pulley and strings shown in are smooth and of negligible mass. For the system to remain in equilibrium, the angle $\theta$ should be:

Two blocks $\mathrm{A}$ and $\mathrm{B}$ pushed against a wall with a force $\mathrm{F}$. The surfaces of $\mathrm{A}$ and $\mathrm{B}$ are rough and the wall is smooth. Which of the following statements is true?

A block of mass $\mathrm{m}$ is in contact with the cart $\mathrm{c}$ as shown The coefficient of static friction between the block and the cart is $\mu$. The acceleration ' $\text{a}$ ' of the cart that will prevent the block from falling satisfies:

 We see the block $Q$ of weight $50 \mathrm{kg}$ placed on a rough surface, the coefficient of static friction between the block and surface is $0.5$. What should be the weight $W$ such that the block does not slip on the surface?