EASY
12th CBSE
IMPORTANT
Earn 100

A horizontal telephone wire 1 km long is lying east-west in earth’s magnetic field. It falls freely to the ground from a height of 10 m. Calculate the emf induced in the wire on striking the ground. Given BH=0.32 G.

Important Questions on Electromagnetic Induction

EASY
12th CBSE
IMPORTANT
A horizontal wire 24 cm long falls in the field of flux density 0.8 T. Calculate the emf induced in it at the end of 3 s, after it was dropped from rest. Suppose the wire moves perpendicular to its length as well as to magnetic field. Take g=9.8 m s2.
EASY
12th CBSE
IMPORTANT
The two rails of a railway track, insulated from each other and the ground are connected to a millivoltmeter. What is the reading of the voltmeter when a train travels at a speed of 180 km h1 along the track, given that the vertical component of the earth’s magnetic field is 0.2×104 Wb m2 and the rails are separated by 1 m?
EASY
12th CBSE
IMPORTANT
A jet plane is travelling west at 450 m s1. If the horizontal component of earth’s magnetic field at that place is 4×104 tesla and the angle of dip is 30°, find the emf induced between the ends of wings having a span of 30 m.
EASY
12th CBSE
IMPORTANT
A straight rod 2 m long is placed in an aeroplane in the east-west direction. The aeroplane lifts itself in the upward direction at a speed of 36 km h1. Find the potential difference between the two ends of the rod if the vertical component of earth’s magnetic field is 143 gauss and angle of dip =30°.
EASY
12th CBSE
IMPORTANT

Figure shows a rectangular conducting loop PQRS in which the arm PQ is free to move. A uniform magnetic field acts in the direction perpendicular to the plane of the loop. Arm PQ is moved with a velocity v towards the arm RS. Assuming that the arms QR, RS and SP have negligible resistances and the moving arm PQ has the resistance R, obtain the expression for the current in the loop

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EASY
12th CBSE
IMPORTANT

Figure shows a rectangular conducting loop PQRS in which the arm PQ is free to move. A uniform magnetic field acts in the direction perpendicular to the plane of the loop. Arm PQ is moved with a velocity v towards the arm RS. Assuming that the arms QR, RS and SP have negligible resistances and the moving arm PQ has the resistance R, obtain the expression for the force.

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EASY
12th CBSE
IMPORTANT

Figure shows a rectangular conducting loop PQRS in which the arm PQ is free to move. A uniform magnetic field acts in the direction perpendicular to the plane of the loop. Arm PQ is moved with a velocity v towards the arm RS. Assuming that the arms QR, RS and SP have negligible resistances and the moving arm PQ has the resistance R, obtain the expression for the power required to move the arm PQ.

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EASY
12th CBSE
IMPORTANT

A rectangular loop PQMN with movable arm PQ of length 10 cm and resistance 2 Ω is placed in a uniform magnetic field of 0.1 T acting perpendicular to the plane of the loop as is shown in the figure. The resistances of the arms MN, NP and MQ are negligible. Calculate the current induced in the loop when arm PQ is moved with velocity 20 m s1.

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