A hydrocarbon $\mathrm{X}$ with molecular formula ${\mathrm{C}}_4{\mathrm{H}}_6$ decolorizes bromine water and forms a white  precipitate in ethanolic ${\mathrm{AgNO}}_3$ solution Treatment of $\mathrm{X}$ with ${\mathrm{HgCl}}_2$ in aqueous ${\mathrm{H}}_2{\mathrm{SO}}_4$ produces a compound, which gives a yellow precipitate when treated with ${\mathrm{I}}_2$ and $\mathrm{NaOH}$. The structure of $\mathrm{X}$ is :

In the compound, 

$\underset{\left(\mathrm{I}\right)}{{\mathrm{CH}}_2}=\underset{\left(\mathrm{II}\right)}{\mathrm{CH}}-\mathrm{C}\underset{\left(\mathrm{III}\right)}{\equiv \mathrm{CH}}$

The most acidic hydrogen atom is

The major product in the following reactions is

${\mathrm{C}}_6{\mathrm{H}}_5-\mathrm{C}\equiv \mathrm{CH}\underset{\left(\mathrm{ii}\right)\mathrm{HI}\left(1\mathrm{eq}\right)}{\overset{\left(\mathrm{i}\right)\mathrm{HCl}\left(1\mathrm{eq}\right)}{\to }}$

Which among the following depicts the correct order of acidity?

The correct sequence of reagents for the following conversion will be

The major product of the following reaction is

In the reaction


$\mathrm{x}$ and $\mathrm{y}$ , respectively, are

Match List$-\mathrm{I}$ with List$-\mathrm{II}:$

Choose the most appropriate match