A line cuts the $x-$axis at a distance of $3$ units to the left of the origin and has slope $-2$. The equation of the line is

The lines $2x + 3y + 7 = 0$ and $27x-18 y + 25= 0$ are

The angle made by the line $\mathrm{x}+\sqrt{3}\mathrm{y}-6=0$, with the positive direction of the $x-$axis is

The equation of the line perpendicular to the line $\mathrm{x}-7\mathrm{y}+5=0$, and having $x-$intercept $3$ is.