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A long U-shaped wire of width l placed in a perpendicular uniform and constant magnetic field B (figure). A wire of length l is slid on the U-shaped wire with a constant velocity v towards right. The resistance of all the wires is r per unit length. At t = 0, the sliding wire is close to the left edge of the fixed U-shaped wire. Draw an equivalent circuit diagram at time t, showing the induced emf as a battery. Calculate the current in the circuit.

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Important Questions on Electromagnetic Induction

HARD
JEE Main/Advance
IMPORTANT

A long U-shaped wire of width l placed in a perpendicular uniform and constant magnetic field B (figure). A wire of length l is slid on the U-shaped wire with a constant velocity v towards right. The resistance of all the wires is r per unit length. At t = 0, the sliding wire is close to the left edge of the fixed U-shaped wire. Draw an equivalent circuit diagram at time t, showing the induced emf as a battery. Calculate the current in the circuit.

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 (a) Calculate the force needed to keep the sliding wire moving with a constant velocity v. (b) If the force needed just after t = 0 is F0, find the time at which the force needed will be F02.
HARD
JEE Main/Advance
IMPORTANT

A wire of mass m and length l can slide freely on a pair of fixed, smooth, vertical rails (figure). A magnetic field B exists in the region in the direction perpendicular to the plane of the rails. The rails are connected at the top end by an initially uncharged capacitor of capacitance C. Find the velocity of the wire at any time (t) after released. Neglecting any electric resistance. (initial velocity of wire is zero)

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HARD
JEE Main/Advance
IMPORTANT

Figure shows a fixed square frame of wire having a total resistance r placed coplanarly with a long, straight wire. The wire carries a current i given by i=i0 cos2πtT. Find (a) the flux of the magnetic field through the square frame, (b) the emf induced in the frame and (c) the heat developed in the frame in the time interval 0 to 10T.

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MEDIUM
JEE Main/Advance
IMPORTANT
The magnetic field in a region is given by B=B0Lxk^, where L is a fixed length. A conducting rod of length L lies along the X-axis between the origin and the point (L, 0, 0). If the rod moves with a velocity v=v0 j^ , find the emf induced between the ends of the rod.
MEDIUM
JEE Main/Advance
IMPORTANT

A straight wire with a resistance of r per unit length is bent to form an angle 2α. A rod of the same wire perpendicular to the angle bisector (of 2α) forms a closed triangular loop. This loop is placed in a uniform magnetic field of induction B. Calculate the current in the wires when the rod moves at a constant speed V.

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EASY
JEE Main/Advance
IMPORTANT

A metal rod of length 15 × 102 m rotates about an axis passing through one end with a uniform angular velocity of 60 rad s1. A uniform magnetic field of 0.1 Tesla exists in the direction of the axis of rotation. Calculate the EMF induced between the ends of the rod.

MEDIUM
JEE Main/Advance
IMPORTANT

In the figure there are two identical conducting rods each of length a rotating with angular speed ω in the directions shown. One end of each rod touches a conducting ring. Magnetic field B exists perpendicular to the plane of the rings. The rods, the conducting rings and the lead wires are resistanceless. Find the magnitude and direction of current in the resistance R.

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MEDIUM
JEE Main/Advance
IMPORTANT
A bicycle is resting on its stand in the east-west direction and the rear wheel is rotated at an angular speed of 100 rpm. If the length of each spoke is 30.0 cm, and the horizontal component of the earth's magnetic field is 2.0×105 T, find the emf induced between the axis and the outer end of a spoke. Neglect centripetal force acting on the free electrons of the spoke.