Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 196

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A mass $M$ is hanging from a spring. If on hanging an additional mass $m$ the string fưrther get stretched by $x$ meters, then the spring constant is

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Important Questions on Simple Harmonic Motion

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Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 197

After falling from a height

h

a mass

m

compresses a spring of force constant

k .

The compression produced in the spring is

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Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 198

A body of mass

8 kg

moving with a velocity of

2 {ms}^{- 1}

comes to the rest, after compressing a spring placed on a frictionless table. If the spring constant is

5000 {Nm}^{- 1}

then compression produced in the spring shall be

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Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 199

A mass of

2 kg

falls from a height

0.4 metre

on a spring of force constant

k = 1960 N m^{- 1} .

The maximum distance upto which the string can be compressed is:

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Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 201

Two masses are connected by a spring as shown in the figure. One of the masses was given velocity $v = 2 k$ as shown in figure where $k$ is the spring constant. Then maximum extension in the spring will be

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Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 202

A wave execute SHM with maximum particle velocity

V_{m}

. If displacement is

\frac{3}{5}

times the amplitude, then particle velocity is,

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Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 203

Two waves are represented as,

y_{1} = a \sin (ω t + \frac{π}{6}), y_{2} = a \cos ω t

. The resultant amplitude is,

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Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 204

The displacement equations for two waves undergoing superposition are, respectively,

y_{1} = 4 \sin ω t

and

y_{2} = 3 \sin (ω t + \frac{π}{2})

. The amplitude of the resultant wave is,

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Alpha Question Bank for Medical: Physics>Chapter 19 - Simple Harmonic Motion>Exercise-1>Q 205

If two waves of same frequency and amplitude superpose to produce resultant of the amplitude of either wave, then their phase difference is,