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A mass M is hanging from a spring. If on hanging an additional mass m the string fưrther get stretched by x meters, then the spring constant is 

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Important Questions on Simple Harmonic Motion

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After falling from a height h a mass m compresses a spring of force constant k. The compression produced in the spring is
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A body of mass 8 kg moving with a velocity of 2 ms-1 comes to the rest, after compressing a spring placed on a frictionless table. If the spring constant is 5000 Nm-1 then compression produced in the spring shall be
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A mass of 2 kg falls from a height 0.4 metre on a spring of force constant k=1960 N m-1. The maximum distance upto which the string can be compressed is:
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Two masses are connected by a spring as shown in the figure. One of the masses was given velocity v=2k as shown in figure where k is the spring constant. Then maximum extension in the spring will be

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A wave execute SHM with maximum particle velocity Vm. If displacement is 35 times the amplitude, then particle velocity is,
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Two waves are represented as, y1=asinωt+π6, y2=acosωt. The resultant amplitude is,
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The displacement equations for two waves undergoing superposition are, respectively, y1=4sinωt and y2=3sinωt+π2. The amplitude of the resultant wave is,
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If two waves of same frequency and amplitude superpose to produce resultant of the amplitude of either wave, then their phase difference is,