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A mass M is performing linear simple harmonic motion, then correct graph for acceleration a and corresponding linear velocity v is

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Important Questions on Simple Harmonic Motion

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A particle moves on the X-axis according to the equation, x=x0sin2ωt. The motion is simple harmonic,
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When two mutually perpendicular simple harmonic motions of same frequency, amplitude and phase are superimposed 
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A simple harmonic motion is given by y=2(4sin3πt+3cos3πt). What is the amplitude of motion if y is in m?
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The position vector of a particle from origin is given by, r=A(i^cosωt+j^sinωt). The motion of the particle is
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The amplitude of a particle executing SHM with the frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is
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At how many maximum points, the velocity of a simple pendulum is same
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Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be
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A particle is executing SHM of frequency 300 Hz and with amplitude 0.1 cm. Its maximum velocity will be