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A mass is suspended from a vertical spring which is executing SHM of frequency 5 Hz. The spring is unstretched at the highest point of oscillation. The maximum speed of the mass is (acceleration due to gravity, g=10 m s-2),

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Important Questions on Oscillations

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A simple pendulum attached to the ceiling of a stationary lift has a time period T . The distance y covered by the lift moving upwards varies with time t as, y=t2, where y is in metres and t in sec. If g=10 m s-2, then the time period of the pendulum will be,
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When the kinetic energy of a body executing SHM is 13 of the potential energy, the displacement of the body is x percent of the amplitude where x is,
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A particle of mass 0.2 kg moves in simple harmonic motion of amplitude 2 cm. If the total energy of the particle is 4×10-5 J, then the time period of the motion is,
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A point performs simple harmonic oscillation of period T and the equation of motion is given by, x=asinω+π6. After the elapsed of what fraction of the time period will the velocity of the point be equal to half its maximum velocity?
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In case of a simple harmonic motion, if the velocity is plotted along the x-axis and the displacement (from the equilibrium position) is plotted along the y-axis, the resultant curve happens to be an ellipse with ratio,

 major axis (along x) minor axis (along y)=20π.

What is the frequency of the simple harmonic motion?

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A ball of mass (m) 0.5 kg is attached to the end of a string having length (L) 0.5 m. The ball is rotated on a horizontal circular path about the vertical axis. The maximum tension that the string can bear is 324 N. The maximum possible value of angular velocity of ball (in radian s-1) is,

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A spring has a certain mass suspended from it and its period for vertical oscillation is T. The spring is now cut into two equal halves and the same mass is suspended from one of the halves. The period of vertical oscillation is now,
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The mass M shown in the figure oscillates in simple harmonic motion with amplitude A. The amplitude of the point P is,

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