How much Ca NO 3 2 in mg must be present in a 50 mL solution with 2 . 35 ppm of Ca ? ρ = 1 g cc - 1

Given, Concentration of Ca = 2 . 35 ppm Volume of solution = 50 mL Parts per million ppm = Mass of solute ( g ) Volume of solution ( mL ) × 10 6 2 . 35 = Mass of Ca in g 50 × 10 6 Mass of Ca = 117 . 5 × 10 - 6 g Moles of Ca = Weight Atomic weight = 117 . 5 × 10 - 6 40 = 2 . 93 × 10 - 6 mol Ca Moles of Ca = moles of Ca NO 3 2 = 2 . 93 × 10 - 6 mol Mass of Ca NO 3 2 = n mole × Molar mass = 2 . 93 × 10 - 6 × 164 = 480 . 5 × 10 - 6 g = 0 . 48 mg .

What is the molarity of NaCl solution having 1 . 52 ppm of Na and the solution density is 1 . 0 g / cm 3 ?

Given, Na = 1 . 52 ppm Density of solution = 1 g cm - 3 Parts per million ppm = mass of solute g mass of solution g × 10 6 So the ⇒ mass of Na = 1 . 52 g Mass of solution = 10 6 g Density = mass g volume mL 1 g ml - 1 = 10 6 Volume of solution mL Volume of solution = 10 3 litre Molarity means moles of solute per litre solution. M = n solute V solution = w M × V solution L = 1 . 52 23 × 10 3 = 6 . 6 × 10 - 5 M .

Calculate the volume of H 2 O to be added to 50 mL of HNO 3 having density 1 . 5 g mL - 1 and 63 . 0 % by weight to have one molar solution.

Given HNO 3 is 63 .0 % by weight. W HNO 3 = 63 . 0 g W Solution = 100 g Moles of HNO 3 = Weight Molecular weight = 63 63 = 1 mole Density of solution = 1 . 5 g ml - 1 Density = mass volume = 1 .5 = 100 V solution mL V solution = 100 1 .5 = 66 .7 ml Molarity means number of moles of solute. Present per litre of the solution M = n solute v solution L = 1 × 1000 66 .7 = 15 M According to dilution law, moles of solute does not change. M 1 V 1 = M 2 V 2 15 × 50 = 1 × V 2 V 2 = 750 ml So added volume of water = V 2 − V 1 = 750 − 50 = 700 ml

In a solution, the concentration of calcium chloride is 5 M and that of MgCl 2 is 5 M . The specific gravity of solution is 1 . 05 . Calculate the concentration of Cl - in the solution in terms of molarity.

5 M CaCl 2 mean 5 moles of CaCl 2 present in 1 litre of CaCl 2 . Or we can say 111 × 5 = 555 g of CaCl 2 is present in 1 litre of solution. Mass of solvent + Mass of MgCl 2 = 1050 - 555 = 495 g 5 m MgCl 2 mean 5 moles of MgCl 2 present in 1 kg of solvent. Or, we can say 475 g of MgCl 2 is present in 1000 g of solvent. So in 1475 g of solution, 475 g of MgCl 2 present. Then mass of MgCl 2 present in 495 g = 475 1475 × 495 = 159 . 4 g Moles of MgCl 2 = 159 . 4 95 = 1 . 68 moles So in 1 litre of solution, 5 moles of CaCl 2 and 1 . 68 moles of MgCl 2 is present. Moles of Cl - = 5 × 2 + 1 . 68 × 2 = 13 . 36 moles Concentration of Cl - = 13 . 36 1 = 13 . 36 M

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IMPORTANT

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A mixture containing $64.0 g H_{2}$ and $64.0 g O_{2}$ is ignited so that water is formed as follows: $2 H_{2} + O_{2} ⟶ 2 H_{2} O$ . Which of the following statements is/are correct?

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Important Questions on Some Basic Concepts, Mole Concept and Stoichiometry

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.4>Q 16

Which of the following is/are correct? The following reaction occurs:

${Na}_{2} {CO}_{3} + 2 HCl ⟶ 2 NaCl + {CO}_{2} + H_{2} O$

$106.0 g$ of ${Na}_{2} {CO}_{3}$ reacts with $109.5 g$ of $HCl$ .

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 1

How much

Ca {({NO}_{3})}_{2}

mg

must be present in a

50 mL

solution with

2.35 ppm

Ca ? (ρ = 1 g {cc}^{- 1})

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 1

What is the molarity of

NaCl

solution having

1.52 ppm

Na

and the solution density is

1.0 g / {cm}^{3} ?

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 2

Calculate the ionic strength (in

g L^{- 1}

) of a solution containing

0.2 M NaCl

and

0.1 M {Na}_{2} {SO}_{4}

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 3

Calculate the volume of

H_{2} O

to be added to

50 mL

{HNO}_{3}

having density

1.5 g {mL}^{- 1}

and

63.0 %

by weight to have one molar solution.

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 4

$5 g$ of $K_{2} {SO}_{4}$ was dissolved in $250 mL$ of solution. How many $mL$ of this solution should be used so that $2.33 g$ of ${BaSO}_{4}$ may be precipitated from ${BaCl}_{2}$ solution?

$K_{2} {SO}_{4} + {BaCl}_{2} ⟶ {BaSO}_{4} + 2 KCl$

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 5

In a solution, the concentration of calcium chloride is

5 M

and that of

{MgCl}_{2}

5 M

. The specific gravity of solution is

1.05

. Calculate the concentration of

{Cl}^{-}

in the solution in terms of molarity.

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 6

Given: Mole fraction of the given sample of

I_{2}

C_{6} H_{6}

0.2

. The molality of

I_{2}

C_{6} H_{6}

A mixture containing 64.0 g H2 and 64.0 g O2 is ignited so that water is formed as follows: 2H2+O2⟶2H2O. Which of the following statements is/are correct?

Important Questions on Some Basic Concepts, Mole Concept and Stoichiometry

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A mixture containing $64.0 g H_{2}$ and $64.0 g O_{2}$ is ignited so that water is formed as follows: $2 H_{2} + O_{2} ⟶ 2 H_{2} O$ . Which of the following statements is/are correct?