A parallel plate capacitor is charged and the charging battery is then disconnected. If the plates of the capacitor are moved closer by means of insulating handles, then

A parallel plate capacitor with air between the plates has a capacitance of $8 \mathrm{pF}$. The separation between the plates is now reduced by half and the space between them is filled with medium of dielectric constant $5$. The value of capacitance of a capacitor in the second case is

The capacity of the conductor does not depend upon

The outer sphere of a spherical air capacitor is earthed. For increasing its capacitance,

A parallel plate capacitor is charged and then disconnected from the charging battery. If the plates are now moved farther apart by pulling them by means of insulating handles, then

A parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge, potential and capacitance respectively are 

The respective radii of the two spheres of a spherical condenser are $12 \mathrm{cm}$ and $9 \mathrm{cm}$. The dielectric constant of the medium between them is $6$. The capacity of the condenser will be

The capacity of a parallel plate condenser is $15 \mu \mathrm{F}$ when the distance between its plates is $6 \mathrm{cm}$. If the distance between the plates is reduced to $2 \mathrm{cm}$, then the capacity of this parallel plate condenser will be 

A parallel plate capacitor of $6 \mu \mathrm{F}$ is connected across $18 \mathrm{V}$ battery and charged. The battery is then disconnected and oil of dielectric constant $\mathrm{k}=2.1$ is introduced between the plates. What will be the charge on capacitor?