A parallel-plate capacitor is charged by a battery which is then disconnected. Then, the distance between the plates is decreased. What are the changes in PD between plates,

A parallel-plate capacitor is charged by a battery which is then disconnected. Then, the distance between the plates is decreased. What are the changes in electric field between plates?

A parallel-plate capacitor is charged by a battery which is then disconnected. Then, the distance between the plates is decreased. What are the changes in stored energy?

A parallel-plate capacitor of plate area A and separation d is charged to a potential difference V. The charging-battery is then disconnected and the plates are pulled apart until their separation is $2\mathrm{d}.$ Write expressions in terms of A , d and V for the new potential difference.

A parallel-plate capacitor of plate area A and separation d is charged to a potential difference V. The charging-battery is then disconnected and the plates are pulled apart until their separation is $2\mathrm{d}.$ Write expressions in terms of A , d and V for the initial and the final stored energies.

A parallel-plate capacitor of plate area A and separation d is charged to a potential difference V. The charging-battery is then disconnected and the plates are pulled apart until their separation is $2\mathrm{d}.$ Write expressions in terms of A, d and V for the work done in increasing the separation between plates.