A parallel plate capacitor is filled with dielectric as shown in the figure. Its capacitance has a ratio with that without dielectric as

A parallel plate capacitor is charged to a certain potential difference. A slab of thickness $3 \mathrm{mm}$ is inserted between the plates and it becomes necessary to increase the distance between the plates by $2.4 \mathrm{mm}$ to maintain the same potential difference. The dielectric constant of the slab is

The capacity of a parallel plate condenser filled with material of dielectric constant $8$ is $16 \mathrm{\mu F}$. Its capacity, if the dielectric is removed, will be

A dielectric plate is introduced between the plates of a parallel plate capacitor to fill the space between the plates. The capacitor is charged and later disconnected from the battery. The dielectric plate is slowly drawn out of the capacitor parallel to the plates. The plot of the potential difference across the plates and the length of the dielectric plate drawn out is

Magnitude of work done during the charging of a condenser from $q=0$ to $q=Q$ is

The energy of a charged capacitor is given by the expression $(q=$ charge on the conductor and $C=$ its capacity)

A parallel plate air condenser of capacity $10 \mu \mathrm{F}$ is charged to a potential of $1000 \mathrm{V}$. The energy of the condenser is