A parallel plate capacitor is of area $6{ \mathrm{cm}}^2$ and a separation $3 \mathrm{mm}.$ The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constants $K_1=10,{ K}_2=12$ and $K_3=14.$ The dielectric constant of a material which when fully inserted in the above capacitor, gives the same capacitance would be:

In the figure shown below, the charge on the left plate of the $10 \mathrm{\mu F}$ capacitor is $-30 \mathrm{\mu C}.$ The charge on the right plate of the $6 \mathrm{\mu F}$ capacitor is:

In the figure shown, after the switch $S$ is turned position $A$ to position $B,$ the energy dissipated in the circuit in terms of capacitance $C$ and total charge $Q$ is: 

The$V$ vs $x$ plot for six identical metal plates of cross-sectional area $A$ is as shown. The equivalent capacitance between $2$ and $5$ is (adjacent plates are placed at a separation $d$),