A parallel plate capacitor of capacity $C_0$ is charged to a potential $V_0$.

$\left(i\right)$ The energy stored in the capacitor when the battery is disconnected and the plate separation is doubled is $E_1$.

$\left(ii\right)$ The energy stored in the capacitor when the charging battery is kept connected and the separation between the capacitor plates is doubled is$E_2$. Then $\frac{E_1}{E_2}$

Two insulating plates are both uniformly charged in such a way that the voltage between them is $V_2-V_1=20 \mathrm{V}$ (i.e., plate $2$ is at a higher potential). The plates are separated by $d=0.1 \mathrm{m}$ and can be treated as infinitely large Fig. An electron is released from rest on the inner surface of plate $1$. What is the velocity when it hits the plate $2$. $\left(e=1.6\times {10}^{-19}\mathrm{C},m_0=9.11\times {10}^{-31} \mathrm{kg}\right)$

What is the potential difference across $2\mu \mathbf{F}$ capacitor in the circuit shown in Fig.

What is the potential difference between points $A$ and $B$ in the circuit shown in Fig.  ?

Two condensers, one of capacity $C$ and the other of capacity $\frac{C}{2}$ are connected to a $V$ volt battery, as shown in figure. The work done in charging both the condensers fully is?