A part of circuit in a steady state along with the currents flowing in the branches, the values of resistances etc, is shown in the figure. Calculate the energy stored in the capacitor C $\left(4\mu F\right)$.

As shown in the figure below, if a capacitor $C$ is charged by connecting it with resistance $R,$ then energy given by the battery will be

Two rods of copper and iron with the same cross-sectional area are joined at $S$ and a steady current $I$ flows through the rods as shown in the figure.

Choose the most appropriate representation of charges accumulated near the junction $S$.

In the given circuit diagram,

$E=5 \mathrm{V}, r=1 \mathrm{\Omega }, R_2=4 \mathrm{\Omega }, R_1=R_3=1 \mathrm{\Omega }$ and $C=3 \mu \mathrm{F}$

Then, what will be the numerical value of charge on each plates of the capacitor.

In the circuit shown, the switch $S$ is initially closed for a long time. The switch is now opened so that the capacitor gets charged.

The time constant of the circuit is

In the circuit shown in the figure, the total charge is $750 \mu C$ and the voltage across capacitor $C_2$ is $20 \mathrm{V}$. Then the charge on capacitor ${\mathrm{C}}_2$ is :

A capacitor of $\mathrm{2 }\mathrm{\mu F}$ is charged as shown in the diagram. When the switch $\mathit{\text{S}}$ is turned to position $2$, the percentage of its stored energy dissipated is