EASY
JEE Main
IMPORTANT
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A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

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Important Questions on Simple Harmonic Motion

EASY
JEE Main
IMPORTANT
A particle executing SHM of amplitude 4 cm and T=4 s. The time taken by it to move from a positive extreme position to half the amplitude is
MEDIUM
JEE Main
IMPORTANT
Two simple harmonic motions are represented by the equations y1=0.1sin100πt+π3 and y2=0.1cosπt. The phase difference of velocity of the particle 1 with respect to the velocity of particle 2 at a time t=0 is
EASY
JEE Main
IMPORTANT
A particle executing simple harmonic motion has an amplitude of 6 cm. Its acceleration at a distance of 2 cm from the mean position is 8 cm s-2. The maximum speed of the particle is
MEDIUM
JEE Main
IMPORTANT
A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, the velocity of the particle is 10 cm s-1. The distance of the particle from the mean position when its speed becomes 5 cm s-1 is
EASY
JEE Main
IMPORTANT
The maximum velocity of a simple harmonic motion represented by y=3sin100t+π6 is given by
EASY
JEE Main
IMPORTANT
Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be
EASY
JEE Main
IMPORTANT
Two massless springs of force constants k1 and k2 are joined end to end. The resultant force constant k of the system is
EASY
JEE Main
IMPORTANT
A light spring of constant k is cut into two equal parts. The spring constant of each part is