A particle has initial velocity $2\hat{\mathrm{i}}+3\hat{\mathrm{j}} \mathrm{unit}$ and acceleration $0.3\hat{\mathrm{i}}+0.2\hat{\mathrm{j}} \mathrm{unit}$ The magnitude of velocity after $10 \mathrm{s}$ will be :

The velocity of a projectile at the initial point $A$ is $(2\hat{\mathrm{i}}+3\hat{\mathrm{j}}) \mathrm{m} {\mathrm{s}}^{-1}.$ It's velocity (in $\mathrm{m} {\mathrm{s}}^{-1}$) at point $B$ is:

A body is moving with velocity $30 \mathrm{m}/\mathrm{s}$ towards east. After $10$ seconds its velocity becomes $40 \mathrm{m}/\mathrm{s}$ towards north. The average acceleration of the body is 

A particle of unit mass undergoes one dimensional motion such that its velocity varies according to $\mathrm{v}\left(\mathrm{x}\right)={\mathrm{bx}}^{-2\mathrm{n}}$, where b and n are constants and $\mathrm{x}$ is the position of the particle. The acceleration of the particle as the function of $\mathrm{x}$, is given by: