A particle is dropped from a height equal to the radius of the earth above the tunnel dug through the earth as shown in the figure.

R : Radius of earth, M : Mass of earth, C: Centre of Earth.

Select the correct statments from given below:

1. Particle will oscillate through the earth to a height R on both sides

2. Particle will execute simple harmonic motion

3. Motion of the particle is periodic

4. Particle passes the centre of earth with a speed  $v =\sqrt{\frac{2\text{GM}}{\text{R}}}$

Consider two solid spheres of radii $R_1=1 \mathrm{m}$,$R_2=2 \mathrm{m}$ and masses $M_1$ and $M_2,$ respectively. The gravitational field due to sphere $\left(1\right)$ and $\left(2\right)$ are shown. The value of $\frac{M_1}{M_2}$ is:

A spherically symmetric gravitational system of particles has mass density $\rho =\left\{\begin{array}{l}{\rho }_0\text{ for }r\le R\\ 0\text{ for }r>R\end{array}\right.$ where, ${\rho }_0$ is a constant. A test mass can undergo circular motion under the influence of the gravitational field of particles. Its speed $v$ as a function of distance $r(0<r<\infty )$ from the centre of the system is represented by

From a solid sphere of mass $M$ and radius $R\text{,}$ a spherical portion of radius $\left(\frac{R}{2}\right)$ is removed as shown in the figure. Taking gravitational potential $V=0$ at $r=\infty ,$ the potential at the centre of the cavity thus formed is ($G=$gravitational constant)