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A particle is executing the motion x=a cos(ωt-θ). The maximum velocity of the particle is

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Important Questions on Simple Harmonic Motion

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A particle executing simple harmonic motion has a time period of 4 s. After how much interval of time from t=0 will its displacement be half of its amplitude?
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The displacement x as a function of time t of a simple harmonic motion is represented by, where A is a positive constant.
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The displacement y of a particle varies with time t, in second as y=2cos(πt+π6) The time period of the oscillations is
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If the acceleration-displacement graph of simple harmonic motion of a particle is given, then the time period of the particle will be

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A student says that he had applied a force, F=-kx on a particle and the particle moved in simple harmonic motion. He refuses to tell whether k is a constant or not. Assume that he has worked only with positive x and no other force acted on the particle. Select the correct option.
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For a particle executing simple harmonic motion, the acceleration is proportional to,
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The displacement of a particle in simple harmonic motion in one time period is,
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The distance moved by a particle in simple harmonic motion in one time period is,