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A particle is moving in a straight line with S.H.M. of amplitude a. At a distance s from the mean position of motion, the particle receives a blow in the direction opposite to that of motion, which instantaneously reduces the velocity to half the initial value. Find the new amplitude.
 

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Important Questions on Oscillations

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A particle is performing linear SHM. If the acceleration and corresponding velocity of the particle are α and v respectively and if we plot v2 on Y axis and α2 on X axis, then the graph will be:
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 A body of mass 36 g moves with S.H.M. of amplitude A=13 cm and time period T=12 s. At time t=0, the displacement x is +13. The shortest time of passage from x=+6.5 cm  to x=-6.5 cm is

 

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The displacement of a particle executing S.H.M. is x=5sin(20πt). Then its frequency will be
 
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A body oscillates with simple harmonic motion according to the equation,x=6cos3πt+π9.The differential equation represented by the equation is
 
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 A Particle performs S.H.M. with amplitude 5 m,period  0.02 s and x=2.5 m at t=0.Which is the correct equation?
 
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A particle moves with simple harmonic motion in a straight line. In first τ s, after starting from rest, it travels a distance a, and in next τ s, it travels 2a in same direction, then:
 
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The graph in the figure shows how the displacement of a particle describing S.H.M. varies with time. Which one of the following statements is not true?

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A simple harmonic motion is given by the equation x=10cos10πt.The phase of S.H.M. after time 2 s is