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A particle moves from the point 2.0i^+4.0j^ m, at t=0 with an initial velocity 5.0i^+4.0j^ m s-1. It is acted upon by a constant force which produces a constant acceleration 4.0i^+4.0j^ m s-2 What is the distance of the particle from the origin at time 2 s

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Important Questions on Kinematics

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An object moving with a speed of 6.25 m s-1 is decelerated at a rate given by, dvdt=-2.5v
where v is instantaneous speed. The time taken by the object to come to rest would be,
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A particle of mass m is at rest at the origin at time t=0. It is subjected to a force Ft=F0e-bt in the x direction. Its speed vt is depicted by which of the following curves?

Hint : Acceleration = Force  Mass 

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From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between Hu and n is :
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A body is thrown vertically upwards. Which one of the following graphs correctly represent the velocity vs time?
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All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up.
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The x, y and z co-ordinates of a particle moving in a 3-D coordinate system are given by x=acosωty=asinωt and z=aωt. The speed of the particle is:
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In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed v more than that of car B. Both the cars start from rest and travel with constant acceleration a1 and a2  respectively. Then v is equal to:
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A particle starts from origin at time t=0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t=5 s?

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