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IMPORTANT
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A particle moves such that its position vector rt=cosωt i^+sinωt j^, where ω is a constant and t is time. Then which of the following statements is true for the velocity vt and acceleration at of the particle:

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Important Questions on Kinematics

MEDIUM
JEE Main
IMPORTANT
A ball is dropped from the top of a 100 m high tower on a planet. In the last 12s before hitting the ground, it covers a distance of 19 m. Acceleration due to gravity (in m s-2 ) near the surface on that planet is______
MEDIUM
JEE Main
IMPORTANT
The distance x covered by a particle in one dimensional motion varies with time t as x2=at2+2bt+c . If the acceleration of the particle depends on x as x-n , where n is an integer, the value of n is _________
MEDIUM
JEE Main
IMPORTANT
One end of a straight uniform 1 m long bar is pivoted on horizontal table. It is released from rest when it makes an angle 30o from the horizontal (see figure). Its angular speed when it hits the table is given as n rad s-1 , where n is an integer. The value of n is ____________
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MEDIUM
JEE Main
IMPORTANT
A particle starts from the origin at t=0 with an initial velocity of 3.0i^ m s-1 and moves in the x-y plane with a constant acceleration 6.0i^+4.0j^ m s-2. The x- coordinate of the particle at the instant when its y- coordinate is 32 m is D meters. The value of D is:
EASY
JEE Main
IMPORTANT
The stream of a river is flowing with a speed of 2 km h-1. A swimmer can swim at a speed of 4 km h-1. The direction of the swimmer with respect to the flow of the river, to cross the river straight, is
HARD
JEE Main
IMPORTANT
The position of a particle as a function of time t, is given by xt=at+bt2-ct3 where a, b and c are constants. When the particle has zero acceleration, then its velocity will be:
EASY
JEE Main
IMPORTANT
The position vector of a particle changes with time according to the relation rt=15t2i^+4-20t2j^. What is the magnitude of the acceleration at t=1?
MEDIUM
JEE Main
IMPORTANT
A particle is moving with a velocity v=Kyi^+xj^, where K is a constant.

The general equation for its path is: