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A particle performing S.H.M. starts from equilibrium position and its time period is 16 seconds. After 2 seconds its velocity is π m s-1. Amplitude of oscillation is cos45°=12

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Important Questions on Oscillations

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A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
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A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
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A coin is placed on a horizontal platform which undergoes vertical simple harmonic motion of angular frequency ω. The amplitude of oscillation is gradually increased. The coin will leave contact with the platform for the first time
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Out of the following functions representing the motion of a particle, which one represents S.H.M.?

(1) y=sinωt-cosωt
(2) y=sin3ωt
(3) y=5cos3π4-3ωt
(4) y=1+ωt+ω2t2

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A simple pendulum performs simple harmonic motion about x=0  with an amplitude A and time period T. The speed of the pendulum at x=A2 will be
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A particle performs simple harmonic motion with amplitude A. Its speed is tripled at the instant that it is at a distance 2 A3 from the equilibrium position. The new amplitude of the motion is
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A body is executing simple harmonic motion with an angular frequency 2 rad s-1. The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm is
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If  x, v and a denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period T, then which of the following does not change with time?