
A particle rests in equilibrium under two forces of repulsion whose centres are at a distance of and from the particle. The forces vary as the cube of the distance. The forces per unit mass are and , respectively. If the particle is slightly displaced towards one of them, the motion is simple harmonic with the time period equal to,


Important Questions on Simple Harmonic Motion


For given spring-mass system, If the time period of small oscillations of block about its mean position is , then find . Assume ideal conditions. The system is in a vertical plane and take

In the figure shown the spring is relaxed and mass m is attached to the spring. The spring is compressed by and released at . Mass collides with the wall and loses two-third of its kinetic energy and returns. Starting from , find the time taken by it to come back to rest again (instant at which spring is again under maximum compression). Take

A block of mass attached with spring of spring constant is executing SHM of amplitude on a smooth horizontal surface as shown in the figure. If another block of mass is gently placed on it, at the instant it passes through the mean position and new amplitude of motion is meter then find . Assuming that two blocks always move together.

Figure shows the kinetic energy of a simple pendulum versus its angle from the vertical. The pendulum bob has mass . If the length of the pendulum is equal to meter, then find

If the angular frequency of small oscillations of a thin uniform vertical rod of mass and length hinged at the point (Fig.) is , then find . The force constant for each spring is and take The springs are of negligible mass.

