EASY
11th CBSE
IMPORTANT
Earn 100

A passenger arriving in a new town wishes to go from the station to a hotel located 10 km away on a straight road from the station. A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 min. What is the magnitude of average velocity? Are the speed and velocity equal?

Important Points to Remember in Chapter -1 - Motion in a Plane from NCERT PHYSICS PART 1 TEXTBOOK FOR CLASS XI Solutions

1. Projectile motion:

(i) Time of flight T= 2usinθg

(ii) Horizontal range R= u2sin2θg

(iii) Maximum height H= u2sin2θ2g

(iv) Trajectory equation (equation of path): y= xtanθ-gx22u2cos2θ= xtanθ1-xR

(v) Velocity after time t, v= ucosθi^+usinθ-gtj^

2. Relative motion:

(i) vAB (velocity of A with respect to B) = vA-vB

(ii) aAB (acceleration of A with respect to B) = aA-aB

3. Crossing river:

(i) A man in a river always moves in the direction of resultant of velocity of man and velocity of river.

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(ii) Velocity with which man moves along the river Vmx= Vr-Vm,Rsinθ

(iii) Velocity with which man moves perpendicular to the river Vmy= Vm,Rcosθ

(iv) Time take to cross the river, t= WVm,Rcosθ

(v) To get minimum time dtdθ= 0θ= 0 

(vi) Drift in this case, d= VrWVm,R

(vii) For shortest path, drift must be zero in this case, and it happens when sinθ= VrVm,R