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A person can see objects placed beyond the distance of 1 m. Find the optical power of the spectacles compensating for the defect of vision for this eye.

Important Questions on Ray Optics

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A near-sighted man can see objects clearly up to a distance of 1.5 m. Calculate the power of the lens of the spectacles necessary for the remedy of this defect.
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If a ray of light incident normally on a plane mirror what is the angle of reflection?
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A ray is incident at 30° angle on plane mirror. What will be deviation after reflection from mirror?
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Two plane mirrors are lying perpendicular to each other, there is lamp in between mirrors. Then number of images of lamp will be
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A man runs towards stationary plane mirror at a speed of 15 m/s. What is the speed of his image with respect to mirror?
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Figure shows two plane mirrors parallel to each other and an object O placed between them. Then the distance of the first three images from the mirror M2 will be : (in cm)

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A ray gets succesively reflection from two mirrors inclined at an angle of 40°. If the angle of incidence on the first mirror is 30° then the net deviation of this ray after two reflections.
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A tall man of height 6 ft, want to see his full image. The required minimum length of the mirror will be:-