The value of one unified atomic mass unit is 1 . 66 × 10 - 27 kg . Calculate the mass of one atom of C 12 in kg .

Given: The value of one unified atomic mass unit is 1 . 66 × 10 - 27 kg . To calculate-the mass of one atom of C 12 in kg . The molar atomic mass of carbon- 12 atom is 12 u which is equal to 12 × 1 . 66 × 10 - 27 Kg or the mass of one atom of C 12 = 1 . 99 × 10 - 26 kg .

Determine the binding energy per nucleon of the nucleus of O 16 8 . Given: mass of hydrogen atom = 1 . 007825 u , mass of neutron = 1 . 008665 u and atomic mass of O 16 8 = 15 . 994915 u .

To determine the binding energy per nucleon of the nucleus of O 16 8 . Given: mass of hydrogen atom = 1 . 007825 u , mass of neutron = 1 . 008665 u and atomic mass of O 16 8 = 15 . 994915 u . The binding energy of the O 16 8 nucleus is given as: BE = [ Z m H + ( A - Z ) m n - m ( X A Z ) ] × C 2 where the letters have their usual meaning. Putting the required values, we get, BE = [ 1 . 007825 + ( 8 ) 1 . 008665 - 15 . 994915 ) ] × C 2 or BE = [ 0 . 137005 ] amu Which gives binding energy as BE = [ 0 . 137005 ) ] × 931 MeV ( ∵ 1 u = 931 MeV ) Binding energy per nucleon= [ 0 . 137005 ) ] × 931 MeV 16 = 7 . 976 MeV

The binding energy per nucleon of O 16 8 is 7 . 97 M e V and that of O 17 8 is 7 . 75 M e V . Find the energy needed to remove a neutron from O 17 8 .

Given:The binding energy per nucleon of O 16 8 is 7 . 97 MeV , the binding energy will be 16 × 7 . 97 = 127 . 52 MeV and given binding energy per nucleon O 17 8 is 7 . 75 MeV , the binding energy will be 17 × 7 . 75 MeV = 131 . 75 MeV The binding energy of the nucleus is given as: BE = [ Z m H + ( A - Z ) m n - m ( X A Z ) ] × C 2 , where the letters have their usual meaning. The energy needed to remove a neutron from O 17 8 will be difference in the binding energy of O 16 8 and O 17 8 since the latter have one extra neutron in it. The required value will be 131 . 75 - 127 . 52 MeV = 4 . 23 MeV .

How much energy is needed to remove a neutron from the nucleus of A 13 l 27 ? Given: mass of A 13 l 27 atom = 26 . 981541 u , mass of A 13 l 26 atom = 25 . 986895 u , mass of neutron = 1 . 008665 u .

Given:The binding energy per nucleon of 13 A l 26 is 25 . 986895 MeV , the binding energy will be 26 × 25 . 986895 = 675 . 65927 MeV and given binding energy per nucleon 13 A l 27 is 7 . 75 MeV , the binding energy will be 17 × 7 . 75 MeV = 131 . 75 MeV The binding energy of the nucleus is given as: BE = [ Z m H + ( A - Z ) m n - m ( X A Z ) ] × C 2 , where the letters have their usual meaning. The energy needed to remove a neutron from Al 27 13 will be difference in the binding energy of A 13 l 26 and Al 27 13 since the latter have one extra neutron in it. The required value will be 131 . 75 - 127 . 52 MeV = 4 . 23 MeV .

E M B I B E

ISC Physics Class 12, Part-2>Chapter 16 - Mass-Energy Equivalence : Nuclear Binding Energy>QUESTIONS>Q 8

HARD

12th ICSE

IMPORTANT

Earn 100

A proton and an antiproton annihilate into two photons of same frequency. What is the wavelength of the photons produced? The mass of a proton is $1.67 \times 10^{- 27} kg$ .

Important Questions on Mass-Energy Equivalence : Nuclear Binding Energy

HARD

12th ICSE

IMPORTANT

ISC Physics Class 12, Part-2>Chapter 16 - Mass-Energy Equivalence : Nuclear Binding Energy>QUESTIONS>Q 9

The rest mass of a proton is

1.67 \times 10^{- 27} kg

. What should be the maximum wavelength of a photon to produce a proton-antiproton pair?

HARD

12th ICSE

IMPORTANT

ISC Physics Class 12, Part-2>Chapter 16 - Mass-Energy Equivalence : Nuclear Binding Energy>QUESTIONS>Q 10

Calculate the energy equivalent (in

M e V

) of one-twelfth of the mass of one atom of a carbon-

12

.

HARD

12th ICSE

IMPORTANT

ISC Physics Class 12, Part-2>Chapter 16 - Mass-Energy Equivalence : Nuclear Binding Energy>QUESTIONS>Q 11

The value of one unified atomic mass unit is

1.66 \times 10^{- 27} kg

. Calculate the mass of one atom of

C^{12}

in

kg

.

HARD

12th ICSE

IMPORTANT

ISC Physics Class 12, Part-2>Chapter 16 - Mass-Energy Equivalence : Nuclear Binding Energy>QUESTIONS>Q 12

Determine the binding energy per nucleon of the nucleus of

{}_{8}O^{16}

. Given: mass of hydrogen atom

= 1.007825 u

, mass of neutron

= 1.008665 u

and atomic mass of

{}_{8}O^{16} = 15.994915 u

.

HARD

12th ICSE

IMPORTANT

ISC Physics Class 12, Part-2>Chapter 16 - Mass-Energy Equivalence : Nuclear Binding Energy>QUESTIONS>Q 13

If we form a lithium nucleus $({}_{3}L i^{7})$ by $4$ neutrons and $3$ protons, then how much energy will be released? $(m_{p} = 1.007825 u, m_{n} = 1.008665 u)$ the mass of the lithium nucleus is $7.01436 u$ .