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A rocket lifts off from the ground and accelerates upwards at $1 m s^{- 2}$ . $20$ seconds after liftoff a piece breaks off from the bottom of the rocket. After breaking off, how much time it takes approximately to reach the ground? (Take $g = 10 m s^{- 2}$ )

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Important Questions on Kinematics

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Kinematics>TS EAMCET - 5 August 2021 Shift 2>Q 9

Two balls are released from the same position at a height of

500 m

above ground, one after the other, with an interval of

1 s .

What is the distance between the two balls when the first hits ground?
(Acceleration due to gravity

g = 10 m / s^{2}

)

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Kinematics>TS EAMCET - 5 August 2021 Shift 2>Q 10

A cyclist traversed half the distance of a linear track with a velocity

10 m s^{- 1} .

The remaining part of the track was covered with a velocity

v_{1}

for half the time and a velocity

v_{2}

for the other half of the time. If

v_{1} + v_{2} = 20 m s^{- 1},

then the average velocity of the cyclist during the completion of the journey through the track is

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Kinematics>TS EAMCET 2018 (04-May Shift-1)>Q 11

The magnitude of acceleration and velocity of a particle moving in a plane, whose position vector

\vec{r} = 3 t^{2} \hat{i} + 2 t \hat{j} + \hat{k}

t = 2 \sec .

are, respectively

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Kinematics>TS EAMCET 2021 (04-Aug Shift-1)>Q 12

A particle moves over a

x y

plane with a constant acceleration

\vec{a} = (4.0 m s^{- 2}) \hat{i} + (4.0 m s^{- 2} \hat{j})

. At the time

t = 0,

the velocity is

(4.0 m s^{- 2}) \hat{i} .

The speed of the particle when it is displaced by

6.0 m

parallel to the

x

-axis is,

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Kinematics>TS EAMCET 2021 (04-Aug Shift-2)>Q 13

The y-component of vector

\vec{A}

+ 3.0 m

. If A makes an angle of

30 °

counter-clockwise from the positive

y

- axis, the magnitude of

\vec{A}

is (assume

\vec{A}

is in

x - y

plane)

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Kinematics>TS EAMCET - 5 August 2021 Shift 1>Q 14

Two bodies were thrown simultaneously from the origin: one straight up and the other, at an angle,

60 °

to the vertical. The initial velocity of each body is equal to

10 m s^{- 1}

Neglecting the air resistance, the distance between the two bodies after

t = 2 s

is (

Use g = 10 m s^{- 2}

)

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Kinematics>TS EAMCET - 5 August 2021 Shift 1>Q 15

A particle leaves the origin with initial velocity

\vec{v} = (3 \hat{i}) m s^{- 1}

and a constant acceleration

\vec{a} = (- 1 \hat{i} - 0.5 \hat{j}) m s^{- 2}

. The position vector of particle, when it reaches its maximum

x

-coordinate, is

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Kinematics>TS EAMCET - 5 August 2021 Shift 2>Q 16

A particle is moving in

x y

-plane crosses the origin at time

t = 0 .

The equation of motion of the particle is

y = 4 x^{2} .

If the velocity of the particle is

\vec{v} = (2 \hat{i} + 2 \hat{j}) m s^{- 1}

and acceleration is

\vec{a} = (a \hat{j}) m s^{- 2}

, then the magnitude of

a

A rocket lifts off from the ground and accelerates upwards at 1 m s-2. 20 seconds after liftoff a piece breaks off from the bottom of the rocket. After breaking off, how much time it takes approximately to reach the ground? (Take g=10 m s-2)

Important Questions on Kinematics

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A rocket lifts off from the ground and accelerates upwards at $1 m s^{- 2}$ . $20$ seconds after liftoff a piece breaks off from the bottom of the rocket. After breaking off, how much time it takes approximately to reach the ground? (Take $g = 10 m s^{- 2}$ )