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A screw gauge with a pitch of $0.5 mm$ and a circular scale with $50$ divisions is used to measure the thickness of a thin sheet of Aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the $45^{th}$ division coincides with the main scale line and that the zero of the main scale is just hidden. If the main scale reading is $0.5 mm$ and the $25^{th}$ division coincides with the main scale line, then the thickness of the sheet is $x mm$ . what is the value of $100 x$ ?

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Important Questions on Experimental Physics

EASY

Physics

IMPORTANT

Physics Crash Course JEE Advanced>Chapter 21 - Experimental Physics>Exercise 1>Q 17

In a screw gauge, there are

100

divisions in circular scale and each main scale division is of

1 mm

. With no gap between the jaws,

98^{th}

divisions coincides with the main scale and zero of main scale is not visible. While measuring the diameter of a ball, the circular scale is between

3 mm

mark and

4 mm

mark.

76^{th}

division of circular scale coincides with the reference line. Select the correct alternative

MEDIUM

Physics

IMPORTANT

Physics Crash Course JEE Advanced>Chapter 21 - Experimental Physics>Exercise 1>Q 18

$1 cm$ of the main scale of vernier calipers is divided into $10 divisions$ . The vernier scale had $n divisions$ , so that least count of the calipers is $0.005 cm$ . The value of $n$ is

MEDIUM

Physics

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Physics Crash Course JEE Advanced>Chapter 21 - Experimental Physics>Exercise 1>Q 19

The diameter of a cylinder is measured using a Vernier calipers with no zero error. It is found that the zero of the Vernier scale lies between

5.10 cm

and

5.15 cm

of the main scale. The Vernier scale has

50

Divisions which coincide with

49

Main scale divisions. The

24^{th}

Division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

x cm

. Find the value of

1000 x

MEDIUM

Physics

IMPORTANT

Physics Crash Course JEE Advanced>Chapter 21 - Experimental Physics>Exercise 1>Q 20

A screw gauge with a pitch of

0.5 mm

and a circular scale with

50

divisions is used to measure the thickness of a thin sheet of Aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the

45^{th}

division coincides with the main scale line and that the zero of the main scale is just hidden. If the main scale reading is

0.5 mm

and the

25^{th}

division coincides with the main scale line, then the thickness of the sheet is

x mm

. what is the value of

100 x

HARD

Physics

IMPORTANT

Physics Crash Course JEE Advanced>Chapter 21 - Experimental Physics>Exercise 1>Q 21

The main scale of a vernier calliper reads in

mm

and its vernier scale is divided into

8

divisions, which coincides with

7

divisions of the main scale. It was also observed that, when the two jaws are brought in contact, the zero of the vernier scale coincided with the zero of the main scale. The edge length of a cube is measured using this vernier calliper. The main scale reads

12 mm

and the

2^{nd}

division of the vernier scale coincides with the main scale. The edge length of the cube is

x mm

. Find the value of

4 x

Important Questions on Experimental Physics

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