A semi-circular sheet of metal whose diameter is $28 \mathrm{cm}$ has been bent in the shape of conical bowl. The depth of the bowl is

The diameier of a cylinder is $7 \mathrm{cm}$ and its height is $16 \mathrm{cm}$ long. The curved surface are of this cylinder is

$\left[\text{ Take }\mathrm{\pi }=\frac{22}{7}\right]$

The radii of the circular ends of a bucket which is the part of a cone are $28 \mathrm{cm}$ and $7 \mathrm{cm}$. The height of the bucket is $45 \mathrm{cm}$. The volume of burket in ${\mathrm{cm}}^3$ is

$\left[\text{ Take }\mathrm{\pi }=\frac{22}{7}\right]$

The tent of a circles is cylindrical upto the height of $3 \mathrm{m}$ and there after its upper portion is conical. The diameter of the base of the tent is $105 \mathrm{m}$ and the slant height of conical part is $63 \mathrm{m}$. The area of canvas required for making this tent is

$\left[\text{ Take }\mathrm{\pi }=\frac{22}{7}\right]$

The ratio of the height and the diameter of a right circular cone is$3: 2$ and its volume is $1078{ \mathrm{cm}}^3$. Its height is?

$\left[\text{ Take }\mathrm{\pi }=\frac{22}{7}\right]$