A simple harmonic motion is represented by $y=5(\sin 3\pi t+\sqrt{3}\cos 3\pi t) \mathrm{cm}$. The amplitude and time period of the motion are

Two particles are executing $\mathrm{SHMs}$. The equations of their motions are

$y_1=10\sin \left(\omega t+\frac{\mathrm{\pi }}{4}\right)$

$y_2=5\sin \left(\omega t+\frac{\sqrt{3}\mathrm{\pi }}{4}\right)$

What is the ratio of their amplitudes?

What is the maximum acceleration of the particle doing the $\mathrm{SHM}$?

$y=2\sin \left[\frac{\mathrm{\pi }t}{2}+\varphi \right]$ where $y$ is in $\mathrm{cm}$.