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A simple pendulum has a length , mass of bob m. The bob is given a charge q coulomb. The pendulum is suspended to a uniform horizontal electric field of strength E as shown in the figure, then calculate the time period of oscillation when the bob is slightly displaced from its mean position is:

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Important Questions on Electrostatics

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Charge 2Q and -Q are placed as shown in figure. The point at which electric field intensity is zero will be:

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The maximum field intensity on the axis of a uniformly charged ring of charge q and radius R will be,
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A charge particle of mass m and charge q is released from rest in a uniform electric field E. Neglecting the effect of gravity, the kinetic energy of the charged particle after t second is -
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The electric field above a uniformly charged nonconducting sheet is E. If the nonconducting sheet is now replaced by a conducting sheet with the charge same as before, the new electric field at the same point is:
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The linear charge density on upper half of a segment of ring is λ and at lower half, it is -λ. The direction of electric field at centre O of ring is:

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+q1 charge is at the centre of an imaginary spherical Gaussian surface 'S', and -q1 charge is placed nearby this +q1 charge inside 'S'. A charge +q2 is located outside this Gaussian surface. Then electric field on Gaussian surface will be
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Three large parallel plates have uniform surface charge densities as shown in the figure. Find out electric field intensity at point P.

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The wrong statement about electric lines of force is -