MEDIUM

JEE Main

IMPORTANT

Earn 100

A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of $θ$ , where $θ$ is the angle by which it has rotated, is given as $k θ^{2}$ . If its moment of inertia is $I$ then the angular acceleration of the disc is:

100% studentsanswered this correctly

Important Questions on Rotational Motion

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 5 - Rotational Motion>JEE Main - 9th April 2019 Shift 1>Q 74

A ball is thrown vertically up (taken as

+ z - a x i s

) from the ground. The correct momentum-height

(p - h)

diagram is:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 5 - Rotational Motion>JEE Main - 9th April 2019 Shift 1>Q 75

The following bodies are made to roll up (without slipping) the same inclined plane from a horizontal plane: (i) a ring of radius

R,

(ii) a solid cylinder of radius

\frac{R}{2}

and (iii) a solid sphere of radius

\frac{R}{4} .

If, in each case, the speed of the center of mass at the bottom of the incline is same, the ratio of the maximum heights they climb is:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 5 - Rotational Motion>JEE Main - 9th April 2019 Shift 2>Q 76

A thin smooth rod of length

L

and mass

M

is rotating freely with angular speed

ω_{0}

about an axis perpendicular to the rod and passing through center. Two beads of mass

m

and negligible size are at the center of the rod initially. The beads of mass

m

and negligible size are at the center of the rod initially. The beads are free to slide along the rod. The angular speed of the system, when the beads reach the opposite ends of the rod, will be:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 5 - Rotational Motion>JEE Main - 9th April 2019 Shift 2>Q 77

A wedge of mass

M = 4 m

lies on a frictionless plane. A particle of mass

m

approaches the wedge with speed

v .

There is no friction between the particle and the plane or between the particle and the wedge. The maximum height climbed by the particle on the wedge is given by:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 5 - Rotational Motion>JEE Main - 9th April 2019 Shift 2>Q 78

Moment of inertia of a body about a given axis is

1.5 k g m^{2} .

Initially the body is at rest. In order to produce a rotational kinetic energy of

1200 J,

the angular acceleration of

20 r a d / s^{2}

must be applied about the axis for a duration of:

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 5 - Rotational Motion>JEE Main - 9th January 2019 Shift 1>Q 79

L

-shaped object, made of thin rods of uniform mass density, is suspended with a string as shown in figure. If

A B = B C,

and the angle made by

A B

with downward vertical is

θ,

then:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 5 - Rotational Motion>JEE Main - 9th January 2019 Shift 2>Q 80

A rod of length $50 c m$ is pivoted at one end. It is raised such that it makes an angle of $30^{o}$ from the horizontal as shown and released from rest. Its angular speed when it passes through the horizontal (in $r a d s^{- 1}$ ) will be $(g = 10 m s^{- 2})$

Question Image

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 5 - Rotational Motion>JEE Main - 8th April 2019 Shift 1>Q 81

A thin circular plate of mass

M

and radius

R

has its density varying as

ρ (r) {=ρ}_{0} r

with

ρ_{0}

as constant and

r

is the distance from its centre. The moment of Inertia of the circular plate about an axis perpendicular to the plate and passing through its edge is

I = a M R^{2}

. The value of the coefficient

a

is:

A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ, where θ is the angle by which it has rotated, is given as kθ2. If its moment of inertia is I then the angular acceleration of the disc is:

Important Questions on Rotational Motion

Learn and Prepare for any exam you want !

A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of $θ$ , where $θ$ is the angle by which it has rotated, is given as $k θ^{2}$ . If its moment of inertia is $I$ then the angular acceleration of the disc is: