MEDIUM
11th West Bengal Board
IMPORTANT
Earn 100

A string can bear a maximum tension of 31.6 N. What maximum number of revolutions per second can be made by a stone of mass 50 gm tied to one end of a 1 m long string so that the string may not break?

Important Questions on Dynamics of Uniform Circular Motion

EASY
11th West Bengal Board
IMPORTANT

Find the maximum speed at which a car can turn round a curve of 30 m radius on a level road if the coefficient of friction between that tyre and the road is 0.4. Take g=10 m/s2

EASY
11th West Bengal Board
IMPORTANT

A sphere of mass 200 gm is attached to an inextensible string of length 130 cm whose upper end is fixed to the ceiling. The sphere is made to describe circle of radius 50 cm. Calculate the time period of one revolution, and tension in the string.

EASY
11th West Bengal Board
IMPORTANT

A bucket full of water is tied with a rope 0.9 m long and revolved in a vertical circle. What would be the minimum speed of the bucket at the highest point so that water may not fall. (Take g=10 m/s2)

EASY
11th West Bengal Board
IMPORTANT

An electric bulb is suspended by a flexible wire from the ceiling of a train. The train goes horizontally round a curved path of radius 250 m. If the velocity of the train is 10 m/s, find the angle the flexible wire makes with downward vertical. (g=10 m/s2)

EASY
11th West Bengal Board
IMPORTANT

A stone is swung uniformly in a horizontal circle at the end of a thread 40 cm long. At what number of revolutions per second, will the thread snap if it is known to do so under a load equal to eightfold weight of the stone? (Take g=10 m/s2)

EASY
11th West Bengal Board
IMPORTANT

A pendulum has length l and the mass of the bob is m. When it makes an angle α with the downward vertical, the velocity of the bob is v. Find the tension in the string at that instant.

MEDIUM
11th West Bengal Board
IMPORTANT

The radius of curvature of a circular road is r and its banking angle is θ. Show that a car can negotiate the bend without skidding with a maximum velocity vmax given by, vmax=r·g(μ+tan θ)1μ tan θ1/2 where μ is the coefficient of friction between the wheel of the car and the ground.

EASY
11th West Bengal Board
IMPORTANT
A truck moves with a uniform velocity v through a convex bridge and a concave bridge having the same radius R. Show that the ratio of the forces exerted by truck at the highest point of the convex bridge and the lowest point of the concave bridge is (gR-v2) : (gR+v2), g being the acceleration due to gravity.