A tank has an inlet $\mathrm{A}$ and two outlet pipes $\mathrm{B} \mathrm{and} \mathrm{C}$. The tank is fully filled by the inlet pipe $\mathrm{A}$ in $5 \mathrm{hours}$. The tank is half emptied by outlet pipes $\mathrm{B} \mathrm{and} \mathrm{C}$ in $1 \mathrm{hr} 30 \mathrm{minutes}$. Now the tank is half-filled. After that, the Inlet pipe $\mathrm{A}$ is opened and the outlet pipe $\mathrm{B}$ is closed. After $\mathrm{n} \mathrm{hours}$, outlet pipe $\mathrm{B}$ is opened and $\mathrm{C}$ is closed. The tank is full after $\mathrm{n} \mathrm{hours}$. Find the total time that inlet $\mathrm{A}$ is open.

Pipe A in comparison to pipe B fills a tank in one fourth time. Pipe C in comparison to pipe A takes 3 times more time to fill the tank. If the three pipes are opened together, the tank is filled in 24 hours. If Pipe C is not opened, how much time will it take to fill the tank?

Of the three pipes, the first two can fill an empty tank in 10.8 and 21.6 hours respectively, while the third pipe can empty the tank in 18 hours. If the tank is empty and all the three pipes are opened together then in how many hours will tank fill?

Quantity $1$: A pipe alone can fill a cistern in $60$ minutes. But due to leakage pipe filled only $80\%$ of the cistern in $60$ minutes. $"X"$ is the capacity of the cistern in litres and due to leakage $60$ litres were leaked out in $1$ hour.

Quantity $2$: $250$ litres.

Two pipes separately take $5$ hours and $8$ hours respectively to fill a tank. The third pipe takes $3.2$ hours to drain out the water from the tank. How much time will all the three pipes take to fill the completely empty tank?